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3 years ago

2. Circle the name of the triangle: isosceles, equilateral, scalene, right

Mathematics

2 answers:

chubhunter [2.5K]3 years ago

6 0

Answer:

its a right triangle

Step-by-step explanation:

since the triangle has the little sqaure inside that means 90° angle

Novosadov [1.4K]3 years ago

4 0

Answer:

right

Step-by-step explanation:

if there's a square in the triangle, that means that it's a 90 degree angle, which means it's a right triangle

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Select the correct answer.

aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

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3 years ago

Line N passes through the points (–1, 4) and (–1, –4). Which is true of line N?

SashulF [63]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~{{ -1}} &,&{{4}}~) 
% (c,d)
&&(~{{ -1}} &,&{{ -4}}~)
\end{array}
\\\\\\
% slope = m
slope \implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{-4-4}{-1-(-1)}\implies \cfrac{-4-4}{-1+1}\implies \stackrel{und efined}{\cfrac{-8}{0}}$

check the picture below.

3 0

4 years ago

a cylindrical grain bin has a radius of 9 feet and a height of 30 feet. What is the surface area of the bin? 1,808.63 ft^2 1949.

Leokris [45]

Surface area of bin:
A = 2(pi)rh + 2(pi)r^2
Assuming you use 3.14 for pi:

A = 2(3.14)(9)(30) + 2(3.14)(81)
A = 2204.28ft^2

6 0

4 years ago

Read 2 more answers

Plz help! Don’t answer if you don’t know

AnnyKZ [126]

The answer is 1+x2 I think

4 0

3 years ago

Using the method of mathematical induction to prove that equalities are true for values of n indicated:

Dima020 [189]

$2^2+4^2+6^2+...(2n)^2=\frac{2n(n+1)(2n+1)}{3};\ n\geq1\\\\chek\ for\ n=1:\\L=2^2=4;\ R=\frac{2\cdot1(1+1)(2\cdot1+1)}{3}=\frac{2\cdot2\cdot3}{3}=4\\L=R\\-----------------------\\
assumption\ for\ n=k\\2^2+4^2+6^2+...+(2k)^2=\frac{2k(k+1)(2k+1)}{3}\\-----------------------\\thesis\ for\ n=k+1\\2^2+4^2+6^2+...+(2k)^2+[2(k+1)]^2=\frac{2(k+1)(k+1+1)[2(k+1)+1]}{3}\\-----------------------$
$proff:\\L=2^2+4^2+6^2+...+(2k)^2+(2k+2)^2=\frac{2k(k+1)(2k+1)}{3}+(2k+2)^2\\\\=\frac{(2k^2+2k)(2k+1)}{3}+\frac{3(2k+2)^2}{3}=\frac{4k^3+2k^2+4k^2+2k+3(4k^2+8k+4)}{3}\\\\=\frac{4k^3+6k^2+2k+12k^2+24k+12}{3}=\boxed{\frac{4k^3+18k^2+26k+12}{3}}\\\\R=\frac{2(k+1)(k+1+1)[2(k+1)+1]}{3}=\frac{(2k+2)(k+2)(2k+2+1)}{3}\\\\=\frac{(2k^2+4k+2k+4)(2k+3)}{3}=\frac{(2k^2+6k+4)(2k+3)}{3}=\frac{4k^3+6k^2+12k^2+18k+8k+12}{3}\\\\=\boxed{\frac{4k^3+18k^2+26k+12}{3}}\\\\L=R$

4 0

3 years ago

2. Circle the name of the triangle: isosceles, equilateral, scalene, right​

2. Circle the name of the triangle: isosceles, equilateral, scalene, right