Answer:
C, D, E
Step-by-step explanation:
The numbers of marbles are:
- Janae - m;
- Jerome - m;
- Gwen - 4(m+2);
- John - 8m+4.
Janae, Jerome, and Gwen combined have
m + m + 4(m+2) = m + m +4m + 8 =6m + 8 marbles.
If John has more marbles than Janae, Jerome, and Gwen combined, then
So, possible answers are
- Janae and Jerome each have 3 marbles;
- Janae and Jerome each have 4 marbles;
- Janae and Jerome each have 5 marbles.
A total of 48 students will not go to college
You did not provide 10 cuts for Tia. This problem cannot be solved.