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4 years ago

assume the two lines ab and xy intersect as in the diagram below. which of the following statements are true

Mathematics

2 answers:

Masja [62]4 years ago

7 0

What are the following statements?

Agata [3.3K]4 years ago

7 0

Answer on apex:

- ARY and XRB are supplementary

-AB and XY are perpendicular

-ARY and XRB are vertical angles

Step-by-step explanation:

Teresa

3 years ago

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What is the surface area

irinina [24]

11cm I think Someone help me with my question 2

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3 years ago

-8m+28=156-12m please help me !!!!

Igoryamba

Answer:

m = 32

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Solve for x. 4(x−214)=−3.7 Enter your answer as a decimal in the box. x =

andre [41]

X = 213.075
First you have to get rid of the 4 and since it’s multiplying you to the opposite and that’s dividing.
-3.7 divided by 4 = -0.925
X - 214 = -0. 925
Then you add 214 to -0.925 and get 213.075

7 0

3 years ago

What kinetic energy has a 4kg shootput thrown with a velocity of 12m/s

Tamiku [17]

Answer:

288J

Step-by-step explanation:

recall the formula for kinetic energy

KE = (1/2) mv²

where m is the mass (= 4kg) and v is the velocity(=12 m/s)

hence

KE = (1/2) (4)(12)² = 288J

7 0

3 years ago

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The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection.

This means that,

Probability that at least one of them needs replacement at the first inspection =

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

3 years ago