Answer:
11. a 8.c thats basically all ik. Srry if i could not answer them all! ;)
The length of each side of a square is 3 in. more than the length of each side of a smaller square. The sum of the areas of the squares is 149 in. $^{2} .$ Find the lengths of the sides of the two squares.
Answer:
128
6
12
48
Step-by-step explanation:
Answer:
1638m²
Step-by-step explanation:
42×39= 1628m²
Problem One
Find AM
AM = 71.5 - 22 = 49.5
Step Two
State the Givens.
AM = 49.5
MN = 71.5
MB = x
MP = 97.5
Step Three
Set up the Proportion
AM : NM :: x : PM
49.5 : 71.5 :: x : 97.5
Substitute and solve
49.5 / 71.5 = x / 97.5 Cross Multiply
49.5 * 97.5 = 71.5 * x Combine the numbers on the left.
4860.375 = 71.5 * x Divide by 71.5
4860.375 / 71.5 = x
x = 67.98
Problem Two
Remark
This is just a straight application of the Pythagorean Theorem
a^2 + b^2 = c^2
a = 10
b = 24
c = ??
10^2 + 24^2 = c^2
100 + 576 = c^2
676 = c^2
sqrt(c^2) = sqrt(676)
c = 26 <<<< answer
