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Strike441 [17]
3 years ago
13

The width of a virus is 2.0 x 10 to the(-7)th meter. Write this number in standard decimal notation

Mathematics
1 answer:
nikklg [1K]3 years ago
8 0

2×10^(-7)=0.0000002m

You have 6 zeros in front of 2.

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Amy has completed 21 deliveries so far this week.she needs to make 60 deliveries for the week.what percentage of her deliveries
Nonamiya [84]

Answer:

65% to go or 35% already delivered

Step-by-step explanation:

Amy has completed 35% of her deliveries since 21/60 is .35

If the question is how much she has left, Amy needs to complete 65% more of her deliveries.

If the question is how much she has completed, she has delivered 35% of her deliveries.

7 0
3 years ago
A survey shows that 45% of the respondents pick option A. Given that 50 people replied, what is the standard error of the propor
QveST [7]
The formula for the standard error is this:
σM = σ / √N

where
σM is the standard error
σ is the standard deviation
N is the number of samples

So,
σM = 0.45 / √50
σM = 0.0636 or 6.36%

The standard error is 0.0636
3 0
3 years ago
Read 2 more answers
CAN SOMEONE WHO KNOWS HOW TO DO THIS PLEASE HELP ME
7nadin3 [17]
Firstly start off with finding the lowest common multiple of 14 and 24. The LCM would be 168. Then you would look at your powers, here you have to choose the highest power of each letter. So 14x^4 and 24x^6 the highest is x^6, then for y it would be y^6 and then for z it would be z^8. So altogether your answer would be 168x^6y^6z^8
4 0
3 years ago
R(x) = (500 + ax) (50 - bx)
o-na [289]

Answer:

x

=

−

500

b

−

50

a

+

R

±

√

250000

b

2

+

2500

a

2

−

100

a

R

+

1000

b

R

+

R

2

+

50000

a

b

2

a

b

Step-by-step explanation:

4 0
3 years ago
F(x) = x2 − x − ln(x) (a) find the interval on which f is increasing. (enter your answer using interval notation.) find the inte
Mekhanik [1.2K]

Answer:

(a) Decreasing on (0, 1) and increasing on (1, ∞)

(b) Local minimum at (1, 0)

(c) No inflection point; concave up on (0, ∞)

Step-by-step explanation:

ƒ(x) = x² - x – lnx

(a) Intervals in which ƒ(x) is increasing and decreasing.

Step 1. Find the zeros of the first derivative of the function

ƒ'(x) = 2x – 1 - 1/x = 0

           2x² - x  -1 = 0

     ( x - 1) (2x + 1) = 0

         x = 1 or x = -½

We reject the negative root, because the argument of lnx cannot be negative.

There is one zero at (1, 0). This is your critical point.

Step 2. Apply the first derivative test.

Test all intervals to the left and to the right of the critical value to determine if the derivative is positive or negative.

(1) x = ½

ƒ'(½) = 2(½) - 1 - 1/(½) = 1 - 1 - 2 = -1

ƒ'(x) < 0 so the function is decreasing on (0, 1).

(2) x = 2

ƒ'(0) = 2(2) -1 – 1/2 = 4 - 1 – ½  = ⁵/₂

ƒ'(x) > 0 so the function is increasing on (1, ∞).

(b) Local extremum

ƒ(x) is decreasing when x < 1 and increasing when x >1.

Thus, (1, 0) is a local minimum, and ƒ(x) = 0 when x = 1.

(c) Inflection point

(1) Set the second derivative equal to zero

ƒ''(x) = 2 + 2/x² = 0

             x² + 2 = 0

                   x² = -2

There is no inflection point.

(2). Concavity

Apply the second derivative test on either side of the extremum.

\begin{array}{lccc}\text{Test} & x < 1 & x = 1 & x > 1\\\text{Sign of f''} & + & 0 & +\\\text{Concavity} & \text{up} & &\text{up}\\\end{array}

The function is concave up on (0, ∞).

6 0
3 years ago
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