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3 years ago

The formula for the area of a trapezoid with altitude k and bases m and n is . A=k/2 (m+n) solve for m..

Mathematics

2 answers:

SashulF [63]3 years ago

5 0

Answer:

$m=A\times\frac{2}{k}-n$

Step-by-step explanation:

Given : The formula for the area of a trapezoid with altitude k and bases m and n is $A=\frac{k}{2}(m+n)$

We have solve for m .

Consider the given formula $A=\frac{k}{2}(m+n)$

Multiply both side by $\frac{2}{k}$ , we have,

$A\times\frac{2}{k}=m+n$

Now subtract n both side, we have,

$A\times\frac{2}{k}-n=m$

Thus, $m=A\times\frac{2}{k}-n$

bija089 [108]3 years ago

3 0

Answer:

When solving for m we get $m=\frac{2A}{k}-n$

Step-by-step explanation:

Given: Formula for Area of trapezoid, $A\:=\:\frac{k}{2}(m+n)$

k is height of the trapezoid and m & n are bases of trapezoid.

We have to solve the formula for m.

Consider the formula,

$A=\frac{k}{2}(m+n)$

$A\times\frac{2}{k}=m+n$

$\frac{2A}{k}=m+n$

$\frac{2A}{k}-n=m$

$m=\frac{2A}{k}-n$

Therefore, When solving for m we get $m=\frac{2A}{k}-n$

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Read 2 more answers

Drawing Conclusions

maksim [4K]

Answer:

Some of the Exponents = -2 that is true, not 2.

Step-by-step explanation:

Let's check one at a time.

(a)The 6 without an exponent is equivalent to the 6 having a 0 exponent.

$6^{0} =1$ and $6^{1}$ = 6 (no exponent. 6 $\neq$ 1 therefore this statement is False.

(b)The sum of the exponents is -2.

let's check , if the base is same we can add the exponents that is the exponent rule.(well established).

if we add exponents in the given expression we get.

$6^{1} 6^{0} 6^{3} =6^{1+0+(-3)} =6^{-2}$ , therefore we can see that the sum of the exponents = -2 this is true.

(c) An equivalent expression is 65.6-7, lets evaluate our above expression, it is equal to $\frac{1}{36}$ which we can see that $\frac{1}{36} \neq 65.6-7$ ,therefore this statement is false as well.