Question

The formula for the area of a trapezoid with altitude k and bases m and n is . A=k/2 (m+n) solve for m..

Answer 1

Answer:

$m=A\times\frac{2}{k}-n$

Step-by-step explanation:

Given : The formula for the area of a trapezoid with altitude k and bases m and n is $A=\frac{k}{2}(m+n)$

We have solve for m .

Consider the given formula  $A=\frac{k}{2}(m+n)$

Multiply both side by $\frac{2}{k}$, we have,

$A\times\frac{2}{k}=m+n$

Now subtract n both side, we have,

$A\times\frac{2}{k}-n=m$

Thus, $m=A\times\frac{2}{k}-n$

Answer 2

Answer:

When solving for m we get $m=\frac{2A}{k}-n$

Step-by-step explanation:

Given: Formula for Area of trapezoid, $A\:=\:\frac{k}{2}(m+n)$

           k is height of the trapezoid and m & n are bases of trapezoid.

We have to solve the formula for m.

Consider the formula,

$A=\frac{k}{2}(m+n)$

$A\times\frac{2}{k}=m+n$

$\frac{2A}{k}=m+n$

$\frac{2A}{k}-n=m$

$m=\frac{2A}{k}-n$

Therefore, When solving for m we get $m=\frac{2A}{k}-n$