A baseball team is in second place with a win to loss ratio of .535. What percent of the games played did the team win?

I need help because idk bbbbbbbbbbbbbbbb

MArishka [77]

Answer:I think it's the second answer

Step-by-step explanation:

Add up all the numbers on the outside of the house to get your answer.

6 0

2 years ago

completa con las razones trigonométricas de cada triángulo rectángulo dado y encuentra el lado faltante aplicando el teorema de

Rus_ich [418]

primero vamos a calcular el lado faltante usando el teorema de pitagoras para poder obtener el lado faltante a

$a=\sqrt[]{hipotenusa^2-cateto^2}$ $a=\sqrt[]{100^2-85^2}=52.68$

a=52.68 m

teniendo el lado faltante podemos calcular las razones trigonometricas

$\sin (55)=\frac{85}{100}=0.85$ $\cos (55)=\frac{52.68}{100}=0.52$ $\tan (55)=\frac{85}{52.68}=1.61$

$\csc (55)=\frac{100}{85}=1.17$ $\sec (55)=\frac{100}{52.68}=1.89$ $\cot (55)=\frac{52.68}{85}=0.61$

4 0

9 months ago

Rectangle base of length 3x cm and width x cm, where x>0. the height is y cm, where y>0. The sum of the length, width and

olchik [2.2K]

Answer:

adD

Step-by-step explanation:

6 0

2 years ago

Please answer: is y – 4x = 9 linear?

Zigmanuir [339]

I think so It’s linear yes

5 0

2 years ago

21 Maria sold small boxes of candy for $1 and

Anna35 [415]

Answer:

There where 10 more Small boxes sold than Large boxes.

Step-by-step explanation:

This is a typical question that can be solved by obtaining a system of two linear equations and solving for each variable.

In principle Linear Equations are algebraic expressions denoting a relationship between a Dependent variable $y$ and an Independent variable $x$ . In a system of Two Linear equations we have two equations of the same variable sets (thus Two Independent variables) so in this case both $y$ and $x$ will be variable terms.

Now with respect to the question and the given information, here our two Variable terms will be the small and the large boxes.

Given Information:

Small Boxes (lets call them $s$ ) cost $1 per box

Large Boxes (lets call them $l$ ) cost $4 per box
Total Number of Boxes sold is 30
Total Profit from sold Boxes is $60

Thus from the above we can obtain one equation denoting the Total Number of Boxes sold and one equation denoting the Total Profit from sold boxes, respectively, as follow:

$s+l=30$ Eqn(1): Total Number of Boxes

$1s+4l=60$ Eqn(2): Total Profit from sold boxes

Now we have a system of two linear equations which we can solve and find the number of small and large boxes, $s$ and $l$ respectively.

From Eqn(1) we see that

$s=30-l$ Eqn(3).

Plugging Eqn(3) in Eqn(2) we can solve for $l$ as:

$1(30-l)+4l=60$

$30-l+4l=60$ Factored out bracket

$3l=60-30$ Gather similar terms on each side and simplify

$3l=30$

$l=\frac{30}{3}$

$l=10$

Plugging in the value for $l=10$ in Eqn(3) we have

$s=30-10\\s=20$

So we know that they were 10 Large Boxes and 20 Small Boxes sold, thus to answer our question, there where 10 more Small boxes sold than Large boxes.

5 0

3 years ago