profit, p = 6 × $50 = $300
losses, l = 120 + 30 + 200 = $350
overall = p - l = -$50
loss of $50
1) x³ + 2x² - x - 2 2) 2x³ + 5x² - 8x - 20 = 0
x²(x + 2) - (x + 2) x²(2x + 5) - 4(2x + 5) = 0
(x + 2)(x² - 1) (2x + 5)(x² - 4) = 0
(x + 2)(x - 1)(x + 1) x = -5/2, +-2
x = -2, 1, -1 << a is the answer.
hope that helps, God bless!
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
Group 1:
μ1 = 59.7
s1 = 2.8
n1 = sample size = 12
Group 2:
μ2 = 64.7
s2 = 8.3
n2 = sample size = 15
α = 0.1
Assume normal distribution and equ sample variance
A.)
Null and alternative hypothesis
Null : μ1 = μ2
Alternative : μ1 < μ2
B.)
USing the t test
Test statistic :
t = (m1 - m2) / S(√1/n1 + 1/n2)
S = √(((n1 - 1)s²1 + (n2 - 1)s²2) / (n1 + n2 - 2))
S = √(((12 - 1)2.8^2 + (15 - 1)8.3^2) / (12 + 15 - 2))
S = 6.4829005
t = (59.7 - 64.7) / 6.4829005(√1/12 + 1/15)
t = - 5 / 2.5108165
tstat = −1.991384
Decision rule :
If tstat < - tα, (n1+n2-2) ; reject the Null
tstat < t0.1,25
From t table :
-t0.1, 25 = - 1.3163
tstat = - 1.9913
-1.9913 < - 1.3163 ; Hence reject the Null
The polygon would have 18 sides. Hope this helps!
