Step 1: Simplify both sides of the equation.
Step 2: Subtract 6x from both sides.
- 65x²+390x+585−6x=6x−6x
- 65x²+384x+585=0
For this equation: a=65, b=384, c=585
Step 3: Use quadratic formula with a=65, b=384, c=585
- x=−b±√b2−4ac/2a
- x=−(384)±√(384)2−4(65)(585)/
- 2(65)
- x=−384±√−4644/130
Therefore, There are no real solutions.
Answer:
no, this reason being is because lets say she needed to know exact angle. she would need to know which rotational way to turn (left right up down, etc.) if this informaton is given to the pilot, they may be left confused and they make the wrong turn or wrong direction.
Step-by-step explanation:
I hope this helps :)
Answer:
I think it would be 2
Step-by-step explanation:
hope it help and was rigjt
Not sure question is complete, assumptions however
Answer and explanation:
Given the above, the function of the population of the ants can be modelled thus:
P(x)= 1600x
Where x is the number of weeks and assuming exponential growth 1600 is constant for each week
Assuming average number of ants in week 1,2,3 and 4 are given by 1545,1520,1620 and 1630 respectively, then we would round these numbers to the nearest tenth to get 1500, 1500, 1600 and 1600 respectively. In this case the function above wouldn't apply, as growth values vary for each week and would have to be added without using the function.
On one hand, the function above could be used as an estimate given that 1600 is the average growth of the ants per week hence a reasonable estimate of total ants in x weeks can be made using the function.
Answer:
The inequality 2.50x>40.00 represents the number of lunches needed to be purchased for the monthly lunch pass to be a better deal.
Step-by-step explanation:
Given that:
Cost of each lunch = $2.50
Cost of monthly lunch pass = $40.00
Number of lunches = x
For making the monthly pass a better deal, the cost of lunches should be greater than the cost of monthly lunches, therefore
Cost of lunch * Number of lunches > Cost of monthly lunch pass
2.50x > 40.00
Hence,
The inequality 2.50x>40.00 represents the number of lunches needed to be purchased for the monthly lunch pass to be a better deal.
