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Firdavs [7]
3 years ago
6

Match the equation with its graph. -2/3x - -1/4y=1/3

Mathematics
1 answer:
Volgvan3 years ago
4 0
If the equation is -(2/3) x - (1/4) y = 1/3, it is a straight line, so you can use some special points to identify the graph.

It is easier is you solve the equation for y:

(1/4)y = - 1/3 - (2/3) x

y = (-4/3) - (8/3)x

That is the slope -y-intercept form of the equation.

That means that the slope is -8/3, and the y-intercept is -4/3.

Use this points to identify the graph:

x = 0 => y = - 4/3 ---> (0, - 4/3)

y = 0 => x = - 1/2 -----> (-1/2, 0)

Now you can punt those two points on the graph and draw the line that joins them.

With this procedure you can find the graph of any straight line.
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never [62]
A = 4 km/jam
r = 1/2
jarak terjauh
s = a/(1 - r)
s = 4/(1 - 1/2)
<span>s = 8 km</span>
3 0
3 years ago
Some roads in Poland have a speed limit of 140 km/h. How fast is this in miles per minute?
zheka24 [161]
1 .47 miles per minute
5 0
3 years ago
What is m&lt;efh =(5×+1)°,m&lt;hfg =62° and m &lt;efg = (18×+11)°, find each measure.​
Naddik [55]

Answer:

m\angle efg=21\°\\\\m\angle hfg=62\°\\\\m\angle efg=83\°

Step-by-step explanation:

Given:

m\angle efh=5x+1\\m\angle hfg=62\\m\angle efg=18x+11

Now, from the figure shown below,

The sum of angle efh and angle hfg is equal to the angle efg. This is true because of the angle addition postulate which states that when two angles are formed with the same vertex and different sides, then their sum is equal to the total angle made by both the sides at the vertex.

Here, point 'f' is the vertex and the sides are 'ef and 'fg'.

Therefore,

m\angle efh+m\angle hfg=m\angle efg

Plug in their values and solve for 'x'. This gives,

5x+1+62=18x+11\\5x+63=18x+11\\18x-5x=63-11\\13x=52\\x=\frac{52}{13}=4

Therefore, the angle measure of each are:

m\angle efg=5x+1=5(4)+1=20+1=21\°\\\\m\angle hfg=62\°\\\\m\angle efg=18x+11=18(4)+11=72+11=83\°

6 0
4 years ago
Point A is located at (?5, 2) on a coordinate grid. Point A is translated 1 unit to the left and 5 units down to create point A'
svp [43]
ANSWER

C) 5.1 units

EXPLANATION

The coordinates of A are (5,2).


If this point is translated 1 unit to the left and 5 units down to create point A'.

Then A' has coordinates

A(5,2)\rightarrow \: A'(5-1,2-5)


A(5,2)\rightarrow \: A'(4, - 3)



The distance between A and A' is calculated using the distance formula,

|AA'| =  \sqrt{ {(5 - 4)}^{2}  +  {(2 -  - 3}^{2} }


|AA'| =  \sqrt{ {(1)}^{2}  +  {(5)}^{2} }


|AA'| =  \sqrt{ 26}


|AA'| =  5.099

We round to the nearest tenth to obtain,

|AA'| =5.1 \: units


The measurement that is closed to the distance is 5.1 units

4 0
4 years ago
A group of married couples takes an IQ test. The average husband's IQ is 105 with an SD of 15 and the average wife's IQ is 110 w
Aloiza [94]

Answer:

Wife' s IQ = 100

0.2% are smarter than their wives.

Step-by-step explanation:

We are given the following information in the question:

Husband:

Mean = 105

SD = 15

Wife:

Mean = 110

SD = 10

Correlation between husband's and wife's IQ = 0.5

a) Let the husbands be represented by X and wives by Y.

Man's IQ = 75

Standardizing the scores, we get:

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

\dfrac{75-105}{15} = -2

We know that if we standardize our scores then:

Z_Y = rZ_X

Putting value, we get:

Z_Y = 0.5(-2) = -1

So,

Y = 110 + (-1)*10 = 100

b) Standard deviation of IQ's of wives married to husbands with IQ of 75 is:

SD = SD_Y\sqrt{1-r^2} = 10\sqrt{1-0.25} = 8.66

We know that a husband of an IQ 75 will have a wife of a mean IQ of 100. So for a man to be smarter than his wife she should have IQ less than 75.

P(Y

8 0
3 years ago
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