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Firdavs [7]
2 years ago
6

Match the equation with its graph. -2/3x - -1/4y=1/3

Mathematics
1 answer:
Volgvan2 years ago
4 0
If the equation is -(2/3) x - (1/4) y = 1/3, it is a straight line, so you can use some special points to identify the graph.

It is easier is you solve the equation for y:

(1/4)y = - 1/3 - (2/3) x

y = (-4/3) - (8/3)x

That is the slope -y-intercept form of the equation.

That means that the slope is -8/3, and the y-intercept is -4/3.

Use this points to identify the graph:

x = 0 => y = - 4/3 ---> (0, - 4/3)

y = 0 => x = - 1/2 -----> (-1/2, 0)

Now you can punt those two points on the graph and draw the line that joins them.

With this procedure you can find the graph of any straight line.
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5.675

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22.7/2= 11.35

11.35/2= 5.675

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2 years ago
Write an equation in POINT-SLOPE FORM of the line that has a slope of -3/5 and passes through the point (2, 1). harrryyy this is
posledela

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y=-3/5x+2.2

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WILL MARK BRAINLIEST!! <br><br> Solve for k.<br><br> -5 &lt; -5k - 15 &lt; 20
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Answer:

-2 > k > -7

Step-by-step explanation:

what you do to one section, you have to do to all

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add 15 to each part

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divide by -5 (when you divide by a negative, it flips the inequality signs!)

-2 > k > -7

7 0
3 years ago
A chocolate company selects 1200 random packages to check their weight it finds that 30 packages have an incorrect weight. how m
Cerrena [4.2K]
150 packages

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2 years ago
a line segment with points p(1 2) and q(4 3) is reflected across the line y=x. What are the new coordinates of the points of the
katen-ka-za [31]

Answer:

The new coordinates of the points of the line segment are p'(2,1) and q'(3,4)

Step-by-step explanation:

we know that

When you reflect a point across the line y= x, the x-coordinate and y-coordinate change places.

so

The rule of the reflection of a point across the line y=x is

(x,y) -----> (y,x)

we have

Points p(1,2) and q(4,3)

Applying the rule of the reflection across the line y=x

p(1,2) ------> p'(2,1)

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therefore

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