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4 years ago

Write the decimal that is 10 times as great as 0.009

Mathematics

1 answer:

irina [24]4 years ago

3 0

0.09 because if you multiple 0.009 by 10 you get 0.09

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Which figures are similar?

Tomtit [17]

Your answer is b ~d and e~f and a~ c

5 0

3 years ago

The measure of one interior angle of a regular polygon is two times the measure of one of its exterior angles. How many sides do

ivann1987 [24]

Answer:

6 sides

Step-by-step explanation:

The measure of one interior angle of a regular polygon is two times the measure of one of its exterior angles. How many sides does this polygon have?

Let us represent:

Sum of Exterior angle as x

Sum of Interior angle as y

Note that:

The sum of the exterior angles of a polygon = 180 - The sum of the interior angles

Hence,

The sum of the exterior angles of a polygon + The sum of the interior angles = 180

x + y = 180

The measure of one interior angle of a regular polygon is two times the measure of one of its exterior angles.

2x = y

Substituting

x + 2x = 180°

3x = 180°

x = 180/3

x = 60°

Solving for y

2x = y

2 × 60° = y

120° = y

Hence,

Sum of Exterior angle as x = 60°

Sum of Interior angle as y = 120°

The number of sides of a polygon is

360°÷ Sum of Exterior angles

= 360° ÷ 60

= 6 sides

6 0

3 years ago

Find the volume of the solid formed by revolving the region bounded by LaTeX: y = \sqrt{x} y = x and the lines LaTeX: y = 1 y =

Strike441 [17]

Answer:

The volume is:

$\displaystyle\frac{37\pi}{10}$

Step-by-step explanation:

See the sketch of the region in the attached graph.

We set the integral using washer method:

$\displaystyle\int_a^b\pi r^2dx$

Notice here the radius of the washer is the difference of the given curves:

$x-\sqrt{x}$

So the integral becomes:

$\displaystyle\int_1^4\pi(x-\sqrt{x})^2dx$

We solve it:

Factor $\pi$ out and distribute the exponent (you can use FOIL):

$\displaystyle\pi\int_1^4x^2-2x\sqrt{x}+x\,dx$

Notice: $x\sqrt{x}=x\cdot x^{1/2}=x^{3/2}$

So the integral becomes:

$\displaystyle\pi\int_1^4x^2-2x^{3/2}+x\,dx$

Then using the basic rule to evaluate the integral:

$\displaystyle\pi\left[\frac{x^3}{3}-\frac{2x^{5/2}}{5/2}+\frac{x^2}{2}\right|_1^4$

Simplifying a bit:

$\displaystyle\pi\left[\frac{x^3}{3}-\frac{4x^{5/2}}{5}+\frac{x^2}{2}\right|_1^4$

Then plugging the limits of the integral:

$\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(4)^{5/2}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]$

Taking the root (rational exponents):

$\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(2)^{5}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]$

Then doing those arithmetic computations we get:

$\displaystyle\frac{37\pi}{10}$

6 0

3 years ago

The enrolment of our school is 800. If 35 % are girls

Anvisha [2.4K]

Answer:

a 7/20. B 13/20

Step-by-step explanation:

800 X 35% = 280

280/800=7/20

6 0

3 years ago

Read 2 more answers

The population of a town is 500,000 in 1990. The population increases at a rate of 5% every five years. What will be the approxi

SVETLANKA909090 [29]

A = P(1+r)^(t/5) A = 500000(1+0.05)^(15/5) A = 500000(1.05)^(15/5) A = 500000(1.05)^3 A = 500000*1.157625 A = 578812.5 Telling us that the population will be about 578,812 people in the year 2005

5 0

3 years ago