<u>Answers</u>
1. (3 + xz)(–3 + xz)
2. (y² – xy)(y² + xy)
3. (64y2 + x2)(–x2 + 64y2)
<u>Explanation</u>
The difference of 2 squares is in the form (a+b)(a-c).
<span>(3 + xz)(–3 + xz) = (3 + xz)(xz -3)
= (xz + 3)(xz - 3)
= x</span>²y²-3xy+3xy-9
<span> =x</span>²y² - 3²<span>
(y</span>² – xy)(y² + xy) = y⁴+xy³-xy³-x²y²
<span> = y</span>⁴ - x²y²
<span>
(64y2 + x2)(–x2 + 64y2)= (64y</span>²+x²)(64y²-x²)
= 4096y⁴-64y²x²+64y²x²-x⁴
= 4096y⁴ - x⁴
First you start off by setting up a Subtraction problem there anything common denominators of 7/8 and two over three verse 7/8 you should get 21/24 invert to over three you should get 16/24 then you would subtract those two anyway to get 5/24 I hope that was helpful get it
Answer:
yes their just 2 answer choices
Answer:
a.bh/2
b.b=A×2/h
c.12
Step-by-step explanation:
......
Answer:
Option (2).
Step-by-step explanation:
Coordinates of points A(-2, 2), B(-1, -1), C(-1, 4) and (0, -2)
By using formula to get the length of any segment having extreme ends at
and
,
d = 
Length of segment AB = 
=
≈ 3.16
Length of segment CD = 
=
≈ 6.08
Length of CD ≈ 2(length of AB)
But length of horizontal segments are equal.
Therefore, function 'f' is vertically stretched to form 'g'.
g(x) = 2f(x)
Now 'f' is translated by 1 unit right,
g(x) = 2f(x - 1)
Option (2) will be the answer.