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Doss [256]
3 years ago
5

he physical plant at the main campus of a large state university receives daily requests to replace florescent light-bulbs. The

distribution of the number of daily requests is Normally distributed with a mean of 47 and a standard deviation of 10. Using the Empirical Rule, what is the approximate percentage of light-bulb replacement requests numbering between 47 and 57?
Mathematics
1 answer:
Stolb23 [73]3 years ago
8 0

Answer:

47.75 %

Step-by-step explanation:

It is a very well known issue that in Standard Normal Distribution  porcentages of all values fall according to:

μ  +   σ       will contain a 68.3 %

μ   +  2σ    will contain  a  95.5 %

μ  +  3σ      will contain  a  99.7 %

However it is extremely  importan to understand that the quantities above mentioned are distributed simmetrically at both sides of the mean, that is,  the intervals are:

[  μ - 0,5σ ;  μ  + 0,5σ ]

[  μ -   1σ ;  μ  +      1σ ]

[  μ -   1.5σ ;  μ  +   1.5σ ]

So we have to take that fact into account when applying the empirical rule. Then

With   mean    μ  =  47       and  σ = 10   is equal to say

values between    47    and     57    (  μ  +   σ  )  we are talking about the second interval, but just half of it.

Then the  approximate porcentage of light-bulb replacement requests is

95.5 /2   =  47.75 %

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PolarNik [594]
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<span>5z – 9 = 36

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z = </span>\frac{45}{5}

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Hence, the answer is D.

Question 2:

<span>5(2z + 4) = 0
</span><span>
10z + 20 = 0

10z = -20

z = </span>\frac{-20}{10}
<span>
z = -2

Hence, the answer is A.

Question 3:

4a + 3(a + 1) = 24

4a + 3a + 3 = 24

7a = 21

a = </span>\frac{21}{7}

a = 3

Hence, the answer is B.

Question 4:

<span>3(4x + 5) = 12

12x + 15 = 12

12x = 12 - 15

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x = </span>\frac{-3}{12} = - \frac{1}{4}

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Question 5:

<span>4x – 8 – 4x = 9

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8 0
3 years ago
Read 2 more answers
Cards are dealt, one at a time, from a standard 52-card deck. a if the first 2 cards are both spades, what is the probability th
ratelena [41]
So we already drew two cards and both of them are spades. So that means there are 50 cards and 11 spades left.

Then third card being spades would be 11 / 50

Now there are 10 spades and 49 cards left.
So the probability for fourth card would be 10 / 49

Fifth card would be 9 / 48.

So the probability of next three cards being spades would be
\dfrac{11}{50}\cdot\dfrac{10}{49}\cdot\dfrac9{48}=\dfrac{33}{3920}\approx\boxed{0.00842}

Hope this helps.
3 0
3 years ago
What is 8/16 as a whole number
just olya [345]

Answer:

2

Step-by-step explanation:

Quick Math

6 0
2 years ago
bastic corporation purchased industrial furnaces for $4015 less 36% and 24%. determine the markup on cost give a regular selling
Aliun [14]
The markup percentage is .40778 -> 40.778% 
$4015 = current price ;  $2852 = original price

To find the mark up percentage:
First, find the difference between the current price and original price.

$4015 - $2852 = $1163

Second, divide the price difference by the current price to get the percentage.
1163/2852 = .40778

Check the math by multiplying the original price by the markup percentage and add the original price to it.

$2852 X .40778 + $2852 = $4015


5 0
3 years ago
I need help on this pls
tresset_1 [31]

Answer:

Hello!

1 on the left in vertical and 1 on the right is adjacent hope that helps.

5 0
2 years ago
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