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ehidna [41]
3 years ago
7

Julie spends $5.62 at the store. Micah spends 5 times as much as Julie. Jeremy spends $6.72 more than Micah. How much money does

each person spend?
Julie: $5.62
Micah:
Jeremy:


Explain how you can use a quick picture to find 3 × 2.7



Sarah is cutting ribbons for a pep rally. The length of each ribbon needs to be 3.68 inches. If she needs 1,000 ribbons, what is the length of ribbon Sarah needs?


Adam is carrying books to the classroom for his teacher. Each books weighs 3.85 pounds. If he carries 4 books, how many pounds is Adam carrying?
Mathematics
1 answer:
avanturin [10]3 years ago
6 0
Micah spent 28.10 dollars, Jeremy spent 34.82 dollars
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Let g be the function given by g(x)=-3x^2-2x+3 evaluate g(-2)
sashaice [31]

g(x) = -3x² - 2x + 3

g(-2) = -3(-2)² - 2(-2) + 3

g(-2) = -12 + 4 + 3 = -5

8 0
3 years ago
The first term of an AP is -7 and the ratio of the eight term to the third term is 7:1 calculate the common difference
alukav5142 [94]

Answer:

the common difference is 6.

Step-by-step explanation:

Given;

first term of an AP, a = -7

let the common difference = d

The third term is written as;

T₃ = a + 2d

The eight term is written as;

T₈ = a + 7d

The ratio of the eight term to third term = 7:1

\frac{T_8}{T_3} = \frac{7}{1} = \frac{a+ 7d}{a + 2d} \\\\7 =  \frac{a+ 7d}{a + 2d}\\\\Recall, a = -7\\\\7 =   \frac{-7+ 7d}{-7 + 2d}\\\\7(-7 + 2d) = -7+ 7d\\\\-49 + 14d = -7 + 7d\\\\14d -7d = -7 + 49\\\\7d = 42\\\\d = \frac{42}{7} \\\\d = 6

Therefore, the common difference is 6.

4 0
2 years ago
What’s the correct answer for this?
Burka [1]

Answer:

AP = 10

Step-by-step explanation:

According to secant-secant theorem

(PB)(AP)=(PD)(PC)

6(AP) = (5)(12)

AP = 60/6

AP = 10

8 0
2 years ago
Read 2 more answers
Simplify the following expression.
MissTica

Answer:

D. 0.054

Step-by-step explanation:

61.904 - 61.85

= 0.054

Therefore, answer choice D is the correct answer.

6 0
2 years ago
Look at picture. Does anybody know the answer I’m lost?
masha68 [24]

Let x,y be the dimensions of the rectangle. We know the equations for both area and perimeter:

A=xy=36

P=2(x+y)=36 \iff x+y=18

So, we have  the following system:

\begin{cases}xy=36\\x+y=18\end{cases}

From the second equation, we can deduce

y=18-x

Plug this in the first equation to get

xy=x(18-x)=-x^2+18=36

Refactor as

x^2-18x+36=0

And solve with the usual quadratic formula to get

x=9\pm3\sqrt{5}

Both solutions are feasible, because they're both positive.

If we chose the positive solution, we have

x=9+3\sqrt{5} \implies y=18-x=18-9-3\sqrt{5}=9-3\sqrt{5}

If we choose the negative solution, we have

x=9-3\sqrt{5} \implies y=18-x=18-9+3\sqrt{5}=9+3\sqrt{5}

So, we're just swapping the role of x and y. The two dimensions of the rectangle are 9+3\sqrt{5} and 9-3\sqrt{5}

6 0
2 years ago
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