Answer:
Step-by-step explanation:
Solution by substitution method
3x-4y=8
and 18x-5y=10
Suppose,
3x-4y=8→(1)
and 18x-5y=10→(2)
Taking equation (1), we have
3x-4y=8
⇒3x=4y+8
⇒x=(
4y+8)/
3 →(3)
Putting x=
(4y+8
)/3 in equation (2), we get
18x-5y=10
18(
(4y+8)
/3) -5y=10
⇒24y+48-5y=10
⇒19y+48=10
⇒19y=10-48
⇒19y= -38
⇒y=-
38
/19
⇒y= -2→(4)
Now, Putting y=-2 in equation (3), we get
x=4y+8
x=
(4(-2)+8)
/3
⇒x=
(-8+8)/
3
⇒x=
0/
3
⇒x=0
∴x=0 and y= -2
Answer:
B) r = C /2π
Step-by-step explanation:
C = 2πr
Divide each side by 2π
C/ 2π = 2πr/ 2π
C/ 2π = r
The answer to this question is B because the opposite of -11 is 11!
It’s larger than a 90 angle it has a bigger angle
Answer:
24t + 270 gallons
Step-by-step explanation:
Given that :
Addition rate 1 = 15 gallons per minute
Addition rate 2 = 9 gallons per minute
Total time spent adding water = half an hour = 30 minutes = 0.5 hour
Time spent adding water at faster rate = t
Time spent addition water at slower rate = (30 - t)
Total number of water added to the pool :
Amount of water added = addition rate * time
Hence,
Amount of water added at faster rate :
(15 gal / min) * t = 15t gallons
Amount added at slower rate :
(9 gal / min) * (30 - t) = (270 - 9t) gallons
Total amount of water added to the pool:
15t gallons + (270 - 9t)gallons
15t + 270 + 9t
24t + 270 gallons