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Liula [17]
3 years ago
10

Calculate the approximate distance point A (5, 3, −2) and point B (2, −4, 8) are from the origin. Round to the nearest tenth.

Mathematics
1 answer:
bulgar [2K]3 years ago
8 0
The distance of A from the origin.
√(5²+3²+(-2)²)= √(25+9+4)
                      =√38
                      =6.2

The  distance of B from the origin

√(2²+(-4)²+8²=√(4+16+64)
                     
                     =√84
                     = 9.2 
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N a game, four cards are labeled N, S, E, and W. Two tiles are numbered 1 and 2. Two discs are red and blue. A player randomly s
algol [13]

Answer: The probability that the player selects a card with S or E, a tile with 2 and a red disc is given as 0.125 (or 1/8)

Step-by-step explanation: If four cards are labelled N, S, E and W, then that means there are a total of four possible outcomes. Also with tiles numbered 1 and 2 there are a total of two possible outcomes when selecting tiles. Then there are two discs in total (one red and one blue) which means there are a total of two outcomes when selecting discs.

To select a card with S would be calculated as follows;

P(S) = Number of required outcomes/Number of all possible outcomes

P(S) = 1/4

P(S) = 0.25

To select a card with E would likewise be calculated as follows;

P(E) = Number of required outcomes/Number of possible outcomes

P(E) = 1/4

P(E) = 0.25

Therefore, the probability that a player selects a card with S or E is derived as follows;

P(S or E) = P(S) + P(E)

P(S or E) = 0.25 + 0.25

P(S or E) = 0.5

The probability that he selects a tile with 2 written on it is calculated as;

P(T2) = Number of required outcomes/Number of all possible outcomes

P(T2) = 1/2

P(T2) = 0.5

The probability that he will select a red disc is calculated as;

P(R) = Number of required outcomes/Number of possible outcomes

P(R) = 1/2

P(R) = 0.5

Therefore, the probability that the player selects a card with S or E, a tile with 2 and a red disc is calculated as;

P(S or E and T2 and R) = 0.5*0.5*0.5

P(S or E and T2 and R) = 0.125

Hence the probability that the player selects a card with S or E, a tile with 2 and a red disc is 0.125 (or 1/8).

5 0
3 years ago
A student who correctly answered 60 questions a test received a score of 75%. How many questions were on the test
Iteru [2.4K]
It would be 45 you take 60 x 75%


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3 years ago
If the data is spread out evenly, the measure of the center that is best to use is the what.
miss Akunina [59]

That would be the mean.

3 0
4 years ago
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Volume of sphere Marcus is using small stone spheres
satela [25.4K]
<h2>Volume of Sphere</h2>

1. What is the radius of the stone sphere?

- To know what is the radius divide is by 2.

  • \large \tt 6 \div 2 = 3

Therefore, the radius of the stone sphere is 3in

2. What is the volume of the stone sphere?

- Using the formula in finding the Volume of Sphere \tt V = \frac{4}{3}\pi r^3 to get the answer. Where the volume of the sphere is \tt\frac{4}{3}\:\:\:\:\pi multiplied by the cube of the radius.

  • \tt V = \frac{4}{3}\pi r^3
  • \tt V = \frac{4}{3}\times 3.14\times 3in^3
  • \tt V = \frac{4}{3}\times 3.14\times 27in
  • \tt V = \frac{4}{3}\times 84.78in
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Therefore, the volume of the stone sphere is 113.04in³

3. Another stone sphere for the garden has a diameter of 10 inches. What is the volume of the stone sphere? Use 3.14 for <em>π</em>, and round to the nearest hundredth.

- Using the formula in finding the Volume of Sphere \tt V = \frac{4}{3}\pi r^3 to get the answer. Where the volume of the sphere is \tt\frac{4}{3}\:\:\:\:\pi multiplied by the cube of the radius.

  • \tt V = \frac{4}{3}\pi r^3
  • \tt V = \frac{4}{3}\times 3.14\times 5in^3
  • \tt V = \frac{4}{3}\times 3.14\times 125in
  • \tt V = \frac{4}{3}\times 392.5in
  • \tt V = \frac{1570in}{3}
  • \tt V = 523.33in^3

<h3>Explanation</h3>

Therefore, the volume of the stone sphere is 523.33in³

<h3>#CarryOnLearning</h3>
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What are the solutions of this quadratic equation?<br> x + 2x=-2
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Answer:

2x=2

Step-by-step explanation:

easy

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