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astra-53 [7]
3 years ago
7

An inscribed angle in a circle measures 16°. What is the measure of the intercepted arc it creates?

Mathematics
2 answers:
USPshnik [31]3 years ago
8 0

The answer is 32 because the inscribed angle is 16 and the intercepted arc would be twice that since you have to half it in the formula.


miskamm [114]3 years ago
6 0

Answer:

<h2>The intercepted arc is 32°.</h2>

Step-by-step explanation:

In this case we need to use the inscribed angle theorem which states that the measure of an inscribed angle is half the measure of its intercepted arc.

So, if the inscrebed angle is 16°, then the intercepted arc is double, according to the inscribed angle theorem, which is 32°.

Therefore, the intercepted arc is 32°.

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see the explanation

Step-by-step explanation:

we know that

A shape with two opposite angles equal to 105° could be a quadrilateral, a parallelogram, a rhombus or a trapezoid

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<em>A parallelogram</em>: A Parallelogram is a flat shape with opposite sides parallel and equal in length. Opposite angles are congruent and consecutive angles are supplementary

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If the parallelogram have two opposite angles equal to 105°, then the measure of each of the other two congruent interior angles must be equal to

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<em>A rhombus</em>: A Rhombus is a flat shape with 4 equal straight sides. A rhombus looks like a diamond. All sides have equal length. Opposite sides are parallel. Opposite angles are congruent and consecutive angles are supplementary

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If the Rhombus have two opposite angles equal to 105°, then the measure of each of the other two congruent interior angles must be equal to

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<em>A trapezoid</em>: A trapezoid is a 4-sided flat shape with straight sides that has a pair of opposite sides parallel

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If the trapezoid have two opposite angles equal to 105°, then the sum of the other two interior angles must be equal to

360^o-2(105^o)=150^o

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