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andrezito [222]
3 years ago
15

The balance of a loan is $2,570 in January, and the monthly payment is $125.50. The relationship between the loan balance, y, an

d the number of monthly payments made since January, x, can be represented by the equation y = 2,570 - 125.50x. In what months does the loan balance, y, meet the condition, $1,600 < y < $2,000? January February March April May June July August September October November December
Mathematics
2 answers:
Eddi Din [679]3 years ago
6 0

Answer:

June, July, and May.

Just finished this assignment :))

Hoochie [10]3 years ago
4 0
1600<2570-125.5x<2000  subtract 2570 from all terms...

-970<-125.5x<-570  divide all terms by -125.5 (and reverse signs because of division by a negative!)
 
7.73>x>4.54  and x is months since January, and since months can only be integers...

x=[5,7]

So January + 5, 6, and 7 respectively are the three months that satisfy the equation...

June, July, and August.





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After 60% discount price will be 156

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156+31.2= $187.2

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What is the answer to -5x+5y=-10 and 3x-3y=5 using substitution
IceJOKER [234]

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Step-by-step explanation: so basically for the first one -5 times x which is 3 is -15 right? and then 5 times y which is 1 is 5 right so -15 plus 5 = -10

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7 0
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27.) Find the sum of the length of line segments EF and CD
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|AB|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2 }

From the image attached the coordinates of the points are E(-1, -1), F(8, -4), C(-7, -4) and D(-1, 2).

Hence the lengths of the line segment EF and CD are:

|EF|=\sqrt{(8-(-1))^2+(-4-(-1))^2} =\sqrt{90}=3\sqrt{10} \\\\CD=\sqrt{(-1-(-7))^2+(-2-(-4))^2}=\sqrt{40}  =2\sqrt{10} \\\\Therefore:\\\\|EF|+|CD|=3\sqrt{10} +2\sqrt{10} =5\sqrt{10}

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