9514 1404 393
Answer:
a. 1.48 seconds
Step-by-step explanation:
You want to find the larger value of t such that h(t) = 10.
-16t^2 +25t +8 = 10
16t^2 -25t +2 = 0 . . . . subtract the left side to get standard form
Using the quadratic formula, we find the values of t to be ...
t = (-(-25) ± √((-25)^2 -4(16)(2)))/(2(16)) = (25±√497)/32
t ≈ 0.08 or 1.48
The ball goes in the hoop about 1.48 seconds after it is thrown.
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<em>Additional comment</em>
The quadratic formula tells us the solution to ...
ax² +bx +c = 0
is given by ...
![x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Here, we have a=16, b=-25, c=2. Of course, our variable is t, not x, but the relation is the same.
Answer:
-12<p<12
Step-by-step explanation:
The answer is D) 400+500+600+700
You round 375<span><span> to 400
round 480 to 500
round 621 to 600
round 685 to 700
Hope this helps! </span></span>
Answer:
243,729,2187
Step-by-step explanation:
It is multiply by 3, so 81*3 and 81*3*3 and 81*3*3*3 which is 243, 729, 2187