Answer:
Options A,C and D are not equivalent
Step-by-step explanation:
1/2log49 + log 20 - log 14
=log 49½ + log 20 - log 14
=1og 7 + log 20 - log 14
=log (7 × 20 / 14)
=log 10
Answer:
65
Step-by-step explanation:
2 - 3 ( 5 + 2 ) ( 5 - 8 )
= 2 - 3 ( 7 ) ( -3 )
= 2 + 63
= 65
Answer:
(1) ΔMAN ≅ ΔBOY
(2) ΔMAT ≅ ΔRUG
(3) ΔEBN ≅ ΔUHR
(4) ΔTOP ≅ ΔLID
(5) ΔCAT ≅ ΔDOG
(6) ΔITP ≅ ΔLOH
Step-by-step explanation:
The following combinations of the congruent triangle facts will be sufficient to prove triangles congruent.
The combinations are:
(1) SSS (side-side-side) : If three sides of a triangle are congruent to three sides of another triangle then the triangles are congruent.
(2) SAS (side-angle-side) : If two sides and included angle of a triangle are congruent to another triangle then the triangles are congruent.
(3) ASA (angle-side-angle) : If two angles and included side of a triangle are congruent to another triangle then the triangles are congruent.
(4) RHS (right angle-hypotenuse-side) : If the hypotenuse and leg of one right triangle are congruent to the corresponding parts of another right triangle, the right triangles are congruent.
Part (1):
As we are given two triangles.
Side AM = Side OB
Side MN = Side BY
Side AN = Side OY
That means,
ΔMAN ≅ ΔBOY
Part (2):
As we are given two triangles.
Side MA = Side RU
Side MT = Side RG
Side AT = Side UG
That means,
ΔMAT ≅ ΔRUG
Part (3):
As we are given two triangles.
Side EB = Side UH
Side BN = Side HR
Side NE = Side RU
That means,
ΔEBN ≅ ΔUHR
Part (4):
As we are given two triangles.
Side OT = Side IL
Side OP = Side ID
Side PT = Side DL
That means,
ΔTOP ≅ ΔLID
Part (5):
As we are given two triangles.
Side AC = Side OD
Side AT = Side OG
Side TC = Side GD
That means,
ΔCAT ≅ ΔDOG
Part (6):
As we are given two triangles.
Side TP = Side OH
Side IT = Side LO
Side IP = Side LH
That means,
ΔITP ≅ ΔLOH
Answer:
Step-by-step explanation: 6
1
3
To have a function, you can't have the same x-coordinate more than once.
The function given above has x-coordinates 1, 2, 3, 4.
Choices B, C, and D would make the function have a repeat of an x-coordinate.
Only choice A does not repeat an x-coordinate since the x-coordinate of choice A is 0 which is not already in the function already.