All categories

3 years ago

What number has the same value as 14

Mathematics

2 answers:

netineya [11]3 years ago

6 0

14
---- is another way to write 14
1

Yanka [14]3 years ago

5 0

The number that has the same value would be |-14| because when you do the absolute value of -14, it means that it is 14 spaces away from 0, making it equal to 14.

You might be interested in

You have 16 different cuts of flowers and plan to use seven of them how many different selections of the seven flowers are possi

alisha [4.7K]

We can have 11440 different selections.

<u>SOLUTION: </u>

Given, you have 16 different cuts of flowers

And you have planned to use seven out of them.

We have to find how many different selections of the seven flowers are possible. Now, we have to select 7 items out of 16 available items. So we have to use combinations.

Then, 7 out of 16 combination $\rightarrow^{16} \mathrm{c}_{7} \rightarrow \frac{16 !}{(16-7) ! 7 !}$

$\bold{\text{ Since } ^nC_r=\frac{n !}{(r !(n-r) !)}}$

$\begin{array}{l}{\rightarrow \frac{16 !}{9 ! \times 7 !}} \\\\ {\rightarrow \frac{16 \times 15 \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 !}{9 ! \times 7 !}} \\\\ {\rightarrow \frac{16 \times 15 \times 14 \times 13 \times 12 \times 11 \times 10}{7 \times 6 \times 13 \times 12 \times 11 \times 10}} \\\\ {\rightarrow \frac{57657600}{5040}} \\\\ {\rightarrow 11440}\end{array}$

Hence, we can have 11440 different selections.

6 0

3 years ago

SOMEONE HELPP MEEE PLEASEEE THIS IS DUE IN 15 MINS

IrinaK [193]

Answer:

30=3x+6

Step-by-step explanation:

4 0

2 years ago

The question says which statement correctly identifies the line of reflection plzzzzz help me

V125BC [204]

I think that the answer is a

6 0

3 years ago

Read 2 more answers

Let v⃗ 1=⎡⎣⎢033⎤⎦⎥,v⃗ 2=⎡⎣⎢1−10⎤⎦⎥,v⃗ 3=⎡⎣⎢30−3⎤⎦⎥ be eigenvectors of the matrix A which correspond to the eigenvalues λ1=−1, λ2

kaheart [24]

Answer:

- x as a linear combination :

x = -1 v1+ 0 v2+ 1 v3.

- Transpose Ax = (12, -6, -6)

Step-by-step explanation:

Given v1 = (0 3 3),v2 = (1 −1 0), v3 = (3 0 −3) be eigenvectors of the matrix A which correspond to the eigenvalues λ1 = −1, λ2 = 0, and λ3 = 1, respectively, and let x = (−2 −4 0). Express x as a linear combination of v1, v2, and v3, and find Ax .

To write x as a linear combination of v1, v2, and v3

x = -1 v1+ 0 v2+ 1 v3.

To find Ax

Write A = (0 ......3 ......3 )

...................(1 ......-1 ......0)

...................(3 ......0......-3)

Since transpose x = (-2, 4, 0)

Ax =......... (0 ......3......3 )(-2)

...................(1 ......-1 ......0)(4)

...................(3 ......0......-3)(0)

= (0×-2 + 3×4 + 3×0)

...(1×-2 + -1×4 + 0×0)

.. (3×-2 + 0×4 + -3×0)

As = (12)

....(-6)

Transpose Ax = (12, -6, -6)

7 0

3 years ago

Given: AD || BC and AD ≅ BC<br><br>Prove: AB || CD

Nana76 [90]

Answer:

i think E TO E

Step-by-step explanation:

6 0

2 years ago