Answer:
r = 225 Mil/h speed of the airplane in still air
Step-by-step explanation:
Then:
d is traveled distance and r the speed of the airplane in still air
so the first equation is for a 4 hours trip
as d = v*t
d = 4 * ( r + 25) (1) the speed of tail wind (25 mil/h)
Second equation the trip back in 5 hours
d = 5 * ( r - 25 ) (2)
So we got a system of two equation and two unknown variables d and
r
We solve it by subtitution
from equation (1) d = 4r + 100
plugging in equation 2
4r + 100 = 5r - 125 ⇒ -r = -225 ⇒ r = 225 Mil/h
And distance is :
d = 4*r + 100 ⇒ d = 4 * ( 225) + 100
d = 900 + 100
d = 1000 miles
Answer:
Step-by-step explanation:
<u>Use ratios and solve:</u>
- 1 in ÷ 7 ft = x in ÷ 28 ft
- x = 28/7 in
- x = 4 in
Answer:
C. X = 10.247
Step-by-step explanation:
X -4.21 = 6.047
just you will add 4.21 to both sides of the equation
X -4.21 + 4.21 = 6.047 + 4.21
X = 10.247
