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solniwko [45]
3 years ago
13

The volume of a cube is 8 cubic meters. What is the length (in meters) of one edge of the cube?

Mathematics
1 answer:
notka56 [123]3 years ago
3 0

Answer:

2

Step-by-step explanation:

volume=base•width•high

2•2•2=8

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Solve the following probability problem. Give the answer in a
Lesechka [4]

Step-by-step explanation:

The probability of not selecting green or yellow marble is equal to the probability of selecting red and blue marble

n(S) =17

n(A)=5 (red)

n(B)=6 (blue)

answer is 5+6/17

=11/17

8 0
3 years ago
Simplify by combining like terms: 15x +2 - 7 - 5x​
Step2247 [10]

Answer:

10x-5

Step-by-step explanation:

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5 0
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Find the area of the figure. (Sides meet at right angles.)
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3 years ago
Write the standard form equation of the ellipse shown in the graph, and identify the foci.
vlada-n [284]

Answer option A

From the given graph is a Vertical ellipse

Center of ellipse = (-2,-3)

Vertices are (-2,3)  and (-2,-9)

Co vertices are (-6,-3) and (2,-3)

The distance between center and vertices = 6, so a= 6

The distance between center and covertices = 4 , so b= 4

The general equation of vertical ellipse is

\frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2}=1

(h,k) is the center

we know center is (-2,-3)

h= -2, k = -3 , a= 6  and b = 4

The standard equation  becomes

\frac{(x+2)^2}{4^2} + \frac{(y+3)^2}{6^2}=1

\frac{(x+2)^2}{16} + \frac{(y+3)^2}{36}=1

Foci  are (h,k+c)  and (h,k-c)

c=\sqrt{a^2-b^2}

Plug in the a=6  and b=4

c=\sqrt{6^2-4^2}

 c=\sqrt{20}

  c=2\sqrt{5}, we know h=-2  and k=-3

Foci  are   (-2,-3+2\sqrt{5})  and  (-2,-3-2\sqrt{5})

Option A is correct

6 0
3 years ago
Solve the system of equations by any method.
Fofino [41]
The answer is <span>C. (4/9, -2 7/8)</span>
4 0
3 years ago
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