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klio [65]
3 years ago
13

What are the three limits on liability coverage for car insurance

Advanced Placement (AP)
1 answer:
hjlf3 years ago
8 0
PHOTO ID
GOOD CREDIT
and also your car info
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Why do you think some sociologists feel American Society is becoming more secular?
saw5 [17]

Answer:  The reason that this is an important argument is because the United States is a secular society, which means that the social structure is not based on or tied to any one particular religion. In sociology, the process by which a society moves away from a religious framework or foundation is known as secularization.

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What processes in the transparency release carbon dioxide into the atmosphere
levacccp [35]

The process that releases carbon dioxide into the atmosphere is called cellular respiration. In this process, carbon dioxide is emitted or produced along with other metabolites such as lactic acid, aldehydes, acetic acids, and other kinds.


Explanation:

Respiration and decay return carbon to the atmosphere. Fossil fuels (oil, coal, and natural gas) are fashioned from buried remains of organisms. The burning of fossil fuels conjointly releases carbon into the atmosphere.cellular respiration could be a set of metabolic reactions and processes that crop up within the cells of organisms to convert organic chemistry energy from nutrients into ATP(ATP), and so unleash waste merchandise.



5 0
2 years ago
I can’t figure this problem out
Natalka [10]

Answer:

Explanation:

Alright so the way to do this is to use properties of integrals to make our life easier.

So we have:

\int\limits^4_1 {(3f(x)+2)} \, dx

So lets break this up into two different integrals that represent the same area.

\int\limits^4_0 {f(x)} \, dx - \int\limits^1_0 {f(x)} \, dx = \int\limits^4_1 {f(x)} \, dx

Lets think about what is going on up there. The integral from four to zero gives us the area under the curve of f(x) from four to zero. If we subtract this from the integral from one to zero (the area under f from one to zero) we are left with the area under f from four to one! Hence:

\int\limits^4_1 {f(x)} \, dx

But since we have these values we can say that:

-3 - 2 = -5

Which means that \int\limits^4_1 {f(x)} \, dx = -5

So now we can evaluate \int\limits^4_1 {(3f(x)+2)} \, dx

Lets first break up our integrand into two integrals

\int\limits^4_1 {(3f(x)+2)} \, dx = 3\int\limits^4_1{f(x)} \, dx + 2\int\limits^4_1 {} \, dx

Now we can evaluate this:

We know that \int\limits^4_1 {f(x)} \, dx = -5

So:

3(-5)+2[x] where x is evaluated at 4 to 1 so

-15 + 2(3)

So we are left with -15 + 6 = -9

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