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BlackZzzverrR [31]
3 years ago
14

Multipule choice

Mathematics
1 answer:
Evgen [1.6K]3 years ago
6 0
0,-3,2 ⇒ B,C,D
............................
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PLEASE HELP MEEE
Romashka-Z-Leto [24]

Answer:

2x^3 + 9x^2 + 16x + 21.

Step-by-step explanation:

We first multiply the expression in the second parentheses by x , then by +3:

(x + 3)(2x^2 + 3x + 7)

= x(2x^2 + 3x + 7) + 3(2x^2 + 3x + 7)

= 2x^3 + 3x^2 + 7x + 6x^2 + 9x + 21   Now we add like terms:

= 2x^3 + 9x^2 + 16x + 21.

7 0
3 years ago
What are the coordinates of the focus of the parabola?
Vikki [24]

Answer:

(-8,2)

hope it help :)

8 0
3 years ago
Please help me i need your help
yanalaym [24]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Simplify the difference.<br> (6w^2 - 5w - 8) – (7w^2 + 4w - 2)
BlackZzzverrR [31]

Answer:

42w^2-20w^2+16

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Farmer Company purchased equipment on January 1, Year 1 for $82,000. The equipment is estimated to have a 5-year life and a salv
aalyn [17]

Answer:

option (a) $6,240

Step-by-step explanation:

Given:

Purchasing cost of the equipment = $82,000

Estimated life = 5 years

Salvage value = $4,000

Revised expected life = 8 years

Now,

Depreciation per year = \frac{\textup{82,000-4,000}}{\textup{5}}

therefore,

The accumulated Depreciation at the beginning of year 4

= Annual depreciation × years passed

= 15,600 × 3

= $46,800

Thus,

The book value at the beginning of year 4

= Purchasing cost - Depreciation

= $82,000 - $46,800

= $35,200

Now,

The remaining life = Revised estimated life - Years passed

= 8 - 3

= 5 years

therefore,

Depreciation expense =\frac{\textup{book value at the beginning of year 4 - salvage value}}{\textup{Revised estimated life}}

= \frac{\textup{35,200  - 4000}}{\textup{5}}

= $6,240

Hence,

The correct answer is option (a) $6,240

7 0
3 years ago
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