A bunch of bananas cost $4, a pineapple cost $2 more than a bunch of bananas, and 4 apples cost one-half of a pineapple.

a farmer produced 47581 2 oranges of one kind and 651 65 oranges of another kind He mixed these oranges and packed in 296 boxes

storchak [24]

Step-by-step explanation:

I am not sure the scanning of the text went well, as this has some strange gaps in the numbers.

I understand that we have 475812 oranges of one type and 65165 oranges of another type.

we have no information, if these types of oranges have significantly different sizes or weight. so, we have to assume that they are reasonably equal to each other.

therefore, the "different type" statement is just to confuse us. the text could have also said that these were 2 different truck loads of the same type.

we only need to deal with the total number of oranges.

so,

475812 + 65165 = 540977 total oranges

he packs them into 296 boxes.

that makes

540977 / 296 = 1827.625 oranges per box.

these are many oranges for one box in real life.

and it is not a round number, which is strange for a home work or test question if this type.

if the farmer truly put only the same number of oranges in every box, he would have

540977 - 1827×296 = 540977 - 540792 = 185

oranges left over.

in any case, these are all signs that there was probably something wrong with the text. but you see the principle up there. please do the same thing with the real numbers.

6 0

3 years ago

Read 2 more answers

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

Tomtit [17]

Apparently my answer was unclear the first time?

The flux of F across S is given by the surface integral,

$\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S$

Parameterize S by the vector-valued function r(u, v) defined by

$\mathbf r(u,v)=7\cos u\sin v\,\mathbf i+7\sin u\sin v\,\mathbf j+7\cos v\,\mathbf k$

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2. Then the surface element is

dS = n • dS

where n is the normal vector to the surface. Take it to be

$\mathbf n=\dfrac{\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}}{\left\|\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}\right\|}$

The surface element reduces to

$\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\mathbf n\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

$\implies\mathbf n\,\mathrm dS=-49(\cos u\sin^2v\,\mathbf i+\sin u\sin^2v\,\mathbf j+\cos v\sin v\,\mathbf k)\,\mathrm du\,\mathrm dv$

so that it points toward the origin at any point on S.

Then the integral with respect to u and v is

$\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S=\int_0^{\pi/2}\int_0^{\pi/2}\mathbf F(x(u,v),y(u,v),z(u,v))\cdot\mathbf n\,\mathrm dS$

$=\displaystyle-49\int_0^{\pi/2}\int_0^{\pi/2}(7\cos u\sin v\,\mathbf i-7\cos v\,\mathbf j+7\sin u\sin v\,\mathbf )\cdot\mathbf n\,\mathrm dS$

$=-343\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}\cos^2u\sin^3v\,\mathrm du\,\mathrm dv=\boxed{-\frac{343\pi}6}$

4 0

3 years ago

70% of Ms. Miller's class passed the test on the first try. Those who failed were able to retake and half of those students pass

MrRissso [65]

Answer:

85%

Step-by-step explanation:

Calculate how many students passed on their first try. 20 x 70% is 14, so 14 students passed on their first try.
6 students retook the test. Half of 6 is 3. Add 3 to the 14 students that passed earlier.
Calculate the percent with the equation 17/20 = 0.85. 0.85 = 85%.

5 0

3 years ago

Give me three numbers greater than 20 that I have 9 as a factor

Andrew [12]

27, 36, 45...all have factors of 9 and r greater then 20

8 0

3 years ago

Read 2 more answers

Regina had 3/4 of a gallon of orange juice. She drank 1/4 of a gallon of orange juice. What fraction of the juice in the gallon

yKpoI14uk [10]

Answer:

Regina drank 2/4 gal. of orange juice