X^2+14x+48
<span>=x^2+(6+8)x+48 </span>
<span>=x^2+6x+8x+48 </span>
<span>x(x+6)+8(x+6) </span>
<span>(x+6)(x+8) [Ans]
the answer is D</span>
Answer:
9 and 40
21 and 40
Step-by-step explanation:
I just did the test on edg. 2020
Factors of 9:
1,3,9
Factors of 15:
1,3,5,15
Factors of 21:
1,3,7,21
Factors of 40:
1,2,4,5,8,10,20,40
We have to find the pairs of numbers which are relatively prime.
Relatively prime number: The numbers in which gcd 1 are called relative prime numbers.
a.9 and 15
GCD(9,15)=3
9 and 15 are not relatively prime.
b.9 and 40
GCD(9,40)=1
Hence, 9 and 40 are relatively prime.
c.9 and 21
GCD(9,21)=3
9 and 21 are not relatively prime.
d.15 and 21
GCD(15,21)=3
15 and 21 are not relatively prime.
e.21 and 40
GCD(21,40)=1
21 and 40 are relatively prime.
Answer:
diameter 12.81 units to the hundredths
Step-by-step explanation:
Assuming O is the intersection of extensions of PS and QR, at the circumference of T.
PT is chord and TS is perpendicular to PT passing through the centre T. Therefore PS is a perpendicular bisector.
SO = 10/2 = 5
Similarly, RO = 5
Consider right triangle ORT right-angled at R
radius = OT = sqrt(OR^2+RT^2) = sqrt(5^2+4^2) = sqrt(41)
Therefore diameter = 2sqrt(41) = 12.806 (to the third decimal place)
Answer:
65.5
Step-by-step explanation:
Using the relation :
Xbar ± Margin of error
Margin of Error = Zcritical * s/√n
The Zcritical value at 95% = 1.96
Hence,
Margin of Error = 1.96 * 2.5/√60
Margin of Error = 1.96 * 0.3227486
Margin of Error = 0.6326
Lower boundary = 65.5 - 0.6326 = 64.867
Upper boundary = 65.5 + 0.6326 = 66.133
(64.867 + 66.133) / 2
Answer:
just double the number each time.
Step-by-step explanation:
so it would be 1, 2, 4, 8, 16, 32, 64, etc.
