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3 years ago

What is a square root?

2 answers:

8 0

A square root is the number that multiplied by itself is a number

Example:

The squere root of 4 is 2 because 2 times 2 is four ( 2 multiplied by itself is four)

nikklg [1K]3 years ago

6 0

Answer:

a number which produces a specified quantity when multiplied by itself.

Step-by-step explanation:

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Juainta is cutting A piece of construction paper in the shape of a parallelogram two opposite sides of a parallelogram have link

balandron [24]

Answer:

The correct answer is the measure of sides are 4 cm and 7 cm.

Step-by-step explanation:

Juainta is cutting a piece of construction paper in the shape of a parallelogram.

Two opposite sides of a parallelogram have links 5n-6 cm and 3n-2 cm. The third side measures 2n+3 cm.

We know that in a parallelogram, the measure of opposite sides are equal.

∴ 5n - 6 = 3n -2

⇒ 2n = 4

⇒ n = 2.

The length one side is 4 cm and of the other side is 7 cm.

4 0

3 years ago

2 (Picture) CONVERGENT AND DIVERGENT SERIES PLEASE HELP!!

Ivanshal [37]

Answer:

This series is divergent

Step-by-step explanation:

we are given a series

Firstly, we will find nth term

Numerator:

3, 4, 5,...

so, nth term will be

$a_n=n+3$

Denominator:

4,5,6,....

so, nth term will be

$b_n=n+4$

so, we can find it's nth term as

$c_n=\frac{n+3}{n+4}$

we can use divergent test

$\lim_{n \to \infty} c_n=\lim_{n \to \infty} \frac{n+3}{n+4}$

we can divide top and bottom by n

$\lim_{n \to \infty} c_n= \lim_{n \to \infty} \frac{n/n+3/n}{n/n+4/n}$

$\lim_{n \to \infty} c_n= \lim_{n \to \infty} \frac{1+3/n}{1+4/n}$

now, we can plug n=inf

$\lim_{n \to \infty} c_n= \frac{1+0}{1+0}$

$\lim_{n \to \infty} c_n=1$

Since, it is non-zero value

so, this series is divergent

8 0

3 years ago

For his job at the hardware store, Michael distributes 2,345 packages of screws into 5 equal groups for shipping. How many packa

drek231 [11]

$\\
\text{Michael distrinutes 2345 packages of screws into 5 equal groups for shipping.}\\
\\
\text{we need to find the number of packages of screws in each group.}\\
\\
\text{so for this we use the unitary method.}\\
\\
\text{The number of packages of screws in 5 groups}=2345\\
\\
\text{so the number of packages of screws in 1 group}=\frac{2345}{5}\\
\\
=469$