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3 years ago

No one is helping me and i really need help :(

Mathematics

2 answers:

adell [148]3 years ago

6 0

Answer:

option one is correct

Step-by-step explanation:

3 times =15

5times 5 =25

galina1969 [7]3 years ago

4 0

Answer:A

Step-by-step explanation:hope this helps :)

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Answer:

The answer is A

Step-by-step explanation:

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4 years ago

Find the value of N please!!

V125BC [204]

Answer:

n = - 5

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ ⇔ $a^{(m+n)}$

$\frac{a^{m} }{a^{n} }$ ⇔ $a^{(m-n)}$

Consider the left side

$\frac{y^4.y^{n} }{y^2}$

= $\frac{y^{4+n} }{y^2}$

= $y^{4+n-2}$

= $y^{2+n}$ , then

$y^{2+n}$ = $y^{-3}$

Since the bases on both sides are the same, equate the exponents

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6 0

3 years ago

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How do I find out 4)?

Rzqust [24]

Answer:

Step-by-step explanation:

Given expression is,

$\lim_{m \to \infty} \frac{4m^2-6m+1}{3m^2+5m+7}$

By dividing denominator and numerator of the given fraction by m²,

$\lim_{m \to \infty} \frac{\frac{4m^2-6m+1}{m^2} }{\frac{3m^2+5m+7}{m^2} }$

= $\lim_{m \to \infty} \frac{4-\frac{6}{m} +\frac{1}{m^2} }{3+\frac{5}{m} +\frac{7}{m^2} }$

We know that $\lim_{n \to \infty} \frac{1}{n}=0$

$\lim_{m \to \infty} \frac{4-\frac{6}{m} +\frac{1}{m^2} }{3+\frac{5}{m} +\frac{7}{m^2} }=\frac{4-0+0}{3+0+0}$

$=\frac{4}{3}$

Therefore, We can evaluate the limit of the expression by substituting ∞ in for m.

6 0

3 years ago

Please math expert simplify this thanks you

Svetllana [295]

Answer:

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Step-by-step explanation:

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3 years ago

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What is 7(x+6)=3(x+9)

KonstantinChe [14]

Answer:

x= -3.75

Step-by-step explanation:

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4 years ago

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