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3 years ago

8

A birthday celebration meal is $46.20 including tax but not the tip.Find the total cost if a 15% tip is added to the cost of the

meal.

1 answer:

lys-0071 [83]3 years ago

3 0

Answer: The total cost is $53.13

Step-by-step explanation: The cost of the birthday meal is $46.20 excluding the tip. The tip is 15%. Thus $46.20×15%=$6.93

We have to add this amount to the initial cost $46.20+$6.93= $53.13

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P= 2 and r= 6 workout the value of Q, when Q =5p +2r

arlik [135]

Answer:

Q=5(2)+2(6)

Q=10+12

Q=22

22 is your answer

Step-by-step explanation:

3 0

3 years ago

A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th

OlgaM077 [116]

Answer:

Interval [16.34 , 21.43]

Step-by-step explanation:

First step. <u>Calculate the mean</u>

$\bar X=\frac{(23+18+23+12+13+23)}{6}=18.666$

Second step. <u>Calculate the standard deviation</u>

$\sigma =\sqrt{\frac{(23-18.666)^2+(18-18.666)^2+(23-18.666)^2+(12-18.666)^2+(13-18.666)^2+(23-18.666)^2}{6}}$

$\sigma=\sqrt\frac{18.783+0.443+18.783+44.435+5.666+18.783}{6}$

$\sigma=\sqrt{17.815}=4.22$

As the number of data is less than 30, we must use the t-table to find the interval of confidence.

We have 6 observations, our level of confidence DF is then 6-1=5 and we want our area A to be 80% (0.08).

We must then choose t = 1.476 (see attachment)

Now, we use the formula that gives us the end points of the required interval

$\bar X \pm t\frac{\sigma}{\sqrt n}$

where n is the number of observations.

The extremes of the interval are then, rounded to the nearest hundreth, 16.34 and 21.43

6 0

2 years ago

Factor out the coefficient of the variable. 1/3b-1/3

BartSMP [9]

1/3b-1/3
factor out 1/3
1/3(b-1)

hope this helps

5 0

3 years ago

Simplify the expression. (5x2 - x - 7) + (2x2 + 3x + 4)

kifflom [539]

Answer:11+2x

Step-by-step explanation:

(10-7-x)+(4+4+3x)

3-x+8+3x

3+8+3x-x

11+2x

3 0

3 years ago

If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?

bixtya [17]

Answer:

$T_{2} = 200$

Step-by-step explanation:

Given

Geometry Progression

$T_1 = 500$

$T_4 = 32$

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

$T_n = ar^{n-1}$

For first term: Tn = 500 and n = 1

$500 = ar^{1-1}$

$500 = ar^{0}$

$500 = a$

$a = 500$

For fought term: Tn = 32 and n = 4

$32 = ar^{4-1}$

$32 = ar^3$

Substitute 500 for a

$32 = 500 * r^3$

Make r^3 the subject

$r^3 = \frac{32}{500}$

$r^3 = 0.064$

Take cube roots

$\sqrt[3]{r^3} = \sqrt[3]{0.064}$

$r = \sqrt[3]{0.064}$

$r = 0.4$

Using: $T_n = ar^{n-1}$

$n = 2$ $r = 0.4$ and $a = 500$

$T_{2} = 500 * 0.4^{2-1}$

$T_{2} = 500 * 0.4^1$

$T_{2} = 500 * 0.4$

$T_{2} = 200$

<em>Hence, the second term is 200</em>

5 0

3 years ago