Which is the following is equivalent to 60^1/2

there are 11 students in summer school. The teacher took a survey of how many pets the students had in their homes. The students

masya89 [10]

Answer:

the median number for this problem is 4

6 0

3 years ago

The ratio of boys to girls in the band is 3:6 if there are 81 students in the band how many boys are in the band

Alexandra [31]

Answer:

27 boys

Step-by-step explanation:

The ratio of boys to girls is 3 to 6. The total is (3+6) is 9.

Using the ratio of boys to total (3 to 9), we set it equal to the ratio of boys to total students (81)

3 b

---- = -------------

9 81

We can solve this using cross products.

3*81 = 9b

243 = 9b

Divide each side by 9

243/9 =9b/9

27 =b

There are 27 boys

8 0

3 years ago

Kapil's robot starts 70cm from its charging base. It faces the base, then turns 60 degrees clockwise, as shown. Finally, the rob

Semmy [17]

The distance of the robot from the charging base is gotten as; 62 cm

<h3>How to use Cosine Rule?</h3>

From the image attached showing the movement of Kapil's robot, we can use cosine rule to find the value of h which is the distance of the robot from the charging base.

The distance of the robot from the charging base is gotten by;

h = x² + b² - 2xb cos 60

h = 50² + 70² - 2*50*70 * 0.5

h = 62 cm

Read more about Cosine Rule at; brainly.com/question/4372174

#SPJ1

4 0

2 years ago

The Lee family pays an instructor $50 for Joylins 40-minute drum lesson

Lesechka [4]

Answer:

Nice. What is the question?

Step-by-step explanation:

4 0

3 years ago

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago