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Marrrta [24]
4 years ago
9

Question 2.Help! finish the number line

Mathematics
1 answer:
musickatia [10]4 years ago
8 0
The answer is in the picture.

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What would be the third step in simplifying the expression 3 + (9 - 5) 2 ÷ 8?
Julli [10]

Answer:

Third step is divide 8 by 8

Step-by-step explanation:

Ok I'm going to do this step by step

First parenthesis

3+4*2÷8

Then multiply by 2

2+8÷8

Divide 8 by 8

2+1

Add

3

4 0
3 years ago
Which step is part of a proof showing the opposite sides of a parallelogram ABCD are congruent?
lawyer [7]
I don't know if this helps/if you have learned this yet but it is a characteristic of a parallelogram that opposite sides are congruent. If this does not help please respond and I will do my best to help! I don't know if I 100% understand what you are asking! 
8 0
3 years ago
Read 2 more answers
Solve X^2 - 3x - 10 = 0 by using the quadratic formula
stiv31 [10]

Good evening

Answer:

<h2>x = 5 or x = -2</h2>

Step-by-step explanation:

Look at the photo below for the details.

:)

8 0
4 years ago
Read 2 more answers
Dario divides 4/6 yard of rope equally into 1/12 yard pieces for a craft project.How many pieces of rope does Dario have?Use a n
zubka84 [21]

Answer:

Eight pieces

Step-by-step explanation:

Create a number line running from 0 to 4/6.

Label the divisions as 1/6, 2/6, 3/6, and 4/6.

Divide each section in half to get small pieces of length 1/12.

Starting at zero, move to 4/6 on the number line and count the number of pieces as you go.

You count eight pieces, so Dario has eight pieces of rope.

5 0
3 years ago
Read 2 more answers
Two buildings on opposites sides of a highway are 3x^3- x^2 + 7x +100 feet apart. One building is 2x^2 + 7x feet from the highwa
Furkat [3]

Given:

Distance between two buildings = 3x^3- x^2 + 7x +100 feet apart.

Distance between highway and one building = 2x^2 + 7x feet.

Distance between highway and second building = x^3 + 2x^2 - 18 feet.

To find:

The standard form of the polynomial representing the width of the highway between the two building.

Solution:

We know that,

Width of the highway = Distance between two buildings - Distance of both buildings from highway.

Using the above formula, we get the polynomial for width (W) of the highway.

W=3x^3- x^2 + 7x +100-(2x^2 + 7x)-(x^3 + 2x^2 - 18)

W=3x^3- x^2 + 7x +100-2x^2-7x-x^3 -2x^2+18

Combining like terms, we get

W=(3x^3-x^3)+(- x^2 -2x^2-2x^2)+ (7x -7x)+(100 +18)

W=2x^3-5x^2+0+118

W=2x^3-5x^2+118

Therefore, the width point highway is 2x^3-5x^2+118.

3 0
3 years ago
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