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3 years ago

Which of the following is NOT a true statement about the angles shown below?

Mathematics

2 answers:

GaryK [48]3 years ago

4 0

The answer is A because the angle AHD is not 30 degrees it is a 90 degrees angle

Aleks04 [339]3 years ago

4 0

The answer is A because angle ahd is not 30 degrees its 90 degree angle

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Can someone help me solve this.

Amanda [17]

Answer:

equilateral: E

scalene: F

isosceles: G

Step-by-step explanation:

equilateral = all sides are equal

scalene = no sides are equal

isosceles = two sides are equal

4 0

3 years ago

1. 2x - 3y = -1 <br> y = x - 1 <br><br> Find the substitution

irina [24]

It might be x = 4, y = 3 or x = 1 and y = -1 if it’s not I’ll re-calculate it and write it down.

6 0

2 years ago

Pppllllzzzz help i cant sleep tell this is done

Mice21 [21]

The answers would be 12 and -16

4 0

3 years ago

Read 2 more answers

Find the number of sides of a regular polygon given the measure of one interior angle.

dolphi86 [110]

Answer: Number of sides of regular polygon is 2.

But with two sides it can't form polygon.

Step-by-step explanation:

Since we have given that

Measure of one interior angle is given by

$9.144\textdegree$

so, As we know that to get an exterior angle , we will use "Linear pair":

Let exterior angle be x.

$x+9.144\textdegree=180\textdegree\\\\x=180\textdegree-9.144\textdegree\\\\x=170.856\textdegree$

Now, we know the formula for " Number of sides ":

$\text{Number of sides }=\frac{360}{x}\\\\\text{Number of sides }=\frac{360}{170.856}\\\\\text{Number of sides }=2.1\\\\\text{but number of sides can't be in decimal.So,}\\\\\text{Number of sides }=2$

Hence, Number of sides of regular polygon is 2.

But with two sides it can't form polygon.

6 0

4 years ago

1. Find sinθ if cosθ=1/2 and θ terminates in Quadrant IV.

Neko [114]

Answer:-(√3)/2, (√2)/2, -√3, and undefined

Step-by-step explanation:

There are two ways you can solve this. One is with the Pythagorean identity:

sin²θ + cos²θ = 1

The other way is by knowing your unit circle.

1. From the unit circle, we know that cos θ = 1/2 at θ = π/3 and θ = 5π/3. Since θ is in Quadrant IV, then θ = 5π/3. sin (5π/3) = -(√3)/2.

We can check our answer using the Pythagorean identity:

sin²θ + cos²θ = 1

sin²θ + (1/2)² = 1

sin²θ + 1/4 = 1

sin²θ = 3/4

sin θ = ±(√3)/2

Since sine is negative in Quadrant IV, sin θ = -(√3)/2.

We can repeat these steps for the other questions.

2. sin θ = (√2)/2 at θ = π/4 and θ = 3π/4. Since θ is in Quadrant I, θ = π/4. Therefore, cos θ = (√2)/2.

3. cos θ = -1/2 at θ = 2π/3 and θ = 4π/3. Since θ is in Quadrant II, θ = 2π/3. Therefore, sin θ = (√3)/2, and tan θ = sin θ / cos θ = -√3.

4. sin θ = -1 at θ = 3π/2. Therefore, cos θ = 0. tan θ = sin θ / cos θ, so tan θ is undefined.

6 0

3 years ago