4/1&373; I need points ;)
Answer:
No ;
Step-by-step explanation:
Given ;
s2 = 10 ; n2 = 10 ; s1 = 12 ; n1 = 12
Hypothesis :
H0 : σ1² = σ2²
H1 : σ1² ≠ σ2²
The test statistic :
Ftest = s1² / s2² = 12² / 10² = 144 / 100 = 1.44
The Pvalue using the Pvalue from Ftest calculator :
Numerator df = 12 - 1 = 11
Denominator df = 10 - 1 = 9
Pvalue = 0.2969
At α = 0.1
If Pvalue > α ; Fail to reject H0
0.2969 > 0.1 ; Hence, we fail to reject the Null
Hence, we cannot conclude that variation exists
Answer:
6
−
4 x
=
6
x
−
8
x
−
2 Since x
is on the right side of the equation, switch the sides so it is on the left side of the equation.
6
x
−
8
x
−
2
=
6−
4
x Subtract 8
x from 6
x
.
−
2
x
−
2
=
6
−
4
x
Move all terms containing x
to the left side of the equation.
Tap for fewer steps...
Add 4
x
to both sides of the equation.
−
2
x
−
2 + 4 x
= 6 Add −
2
x and 4
x
.
2
x
−
2
=
6
Move all terms not containing
x to the right side of the equation.
Tap for fewer steps...
Add 2
to both sides of the equation.
2
x
=
6
+ 2 Add 6 and 2
.
2
x
=
8
Divide each term by
2 and simplify.
Tap for fewer steps...
Divide each term in
2
x
=
8 by 2
. 2
x
2
= 8 2 Cancel the common factor of
2 . Tap for more steps...
x
=
8 2 Divide 8 by 2
.
x
=
4
6576576576576475463543543653 is the answer:)
