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3 years ago

8

If QR = 6x + 1, PR = 14x-13, and PQ = 5x -2, find PR.

1 answer:

monitta3 years ago

5 0

Answer:

Um I will report ur answer

Step-by-step explanation:

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A house purchased for $230,000 has lost 6% of its value each year for the last four years. What is the house worth now?

lutik1710 [3]

You can use the compound growth to work this out,

Firstly you need to make a multiplier for -6%;
1-(6/100) = 0.94

The you times the amount of money by 0.94 to the power of 4 because you are working out 4 years:
230000*0.94^4 = 179527.26

The answer is $179527.26,
Hope this helps! :)

3 0

3 years ago

Okay can someone pls help me i literally am so confused

masha68 [24]

View answer attached below

5 0

3 years ago

Nestor the clown does the face painting at the city carnival. She paints seven faces every 21 minutes and spend the same amount

Likurg_2 [28]

Answer:

21/F=M

Step-by-step explanation:

3 minutes per face so divide time and faces to get the time.

F=7 M=3

4 0

3 years ago

SOHCAHTOA can anyone help me with this

zvonat [6]

Root of ( 20^2 - 16^2 ) = 12

5 0

3 years ago

Find the annual rate of interest. Principal = 4600 rupees Period = 5 years Total amount = 6440 rupees Annual rate of interest =

Semmy [17]

Answer:

The rate of interest for compounded annually is 6.96 % .

Step-by-step explanation:

Given as :

The principal amount = Rs 4600

The time period = 5 years

The amount after 5 years = Rs 6440

Let The rate of interest = R %

<u>From compounded method</u>

Amount = Principal × $(1+\dfrac{\textrm rate}{100})^{\textrm Time}$

or, Rs 6440 = Rs 4600 × $(1+\dfrac{\textrm R}{100})^{\textrm 5}$

Or, $\frac{6440}{4600}$ = $(1+\dfrac{\textrm R}{100})^{\textrm 5}$

or, 1.4 = $(1+\dfrac{\textrm R}{100})^{\textrm 5}$

Or, $(1.4)^{\frac{1}{5}}$ = 1 + $\dfrac{R}{100}$

or, 1.0696 = 1 + $\dfrac{R}{100}$

or, $\dfrac{R}{100}$ = 1.0696 - 1

Or, $\dfrac{R}{100}$ = 0.0696

∴ R = 0.0696 × 100

I.e R = 6.96

Hence The rate of interest for compounded annually is 6.96 % . Answer

5 0

3 years ago