If alex picked a classmate at random, what is P(B|A) ?

What is the value of cos A?

BlackZzzverrR [31]

Step-by-step explanation:

h²=p²+b²
h²=24²+7²
h²=576+49
h=√625
h=25

tanA=p/h

24/25

its yr ans

hope it helps.

<h2>stay safe healthy and happy....</h2>

3 0

3 years ago

My last of many blurry pictures…

Nesterboy [21]

150 people.

27 is 18% of 150.
10.5 is 7% of 150.
15 is 10% of 150.
19.5 is 13% of 150.
28.5 is 19% of 150.
49.5 is 33% of 150.

7 0

2 years ago

Tres mineros,A,B,C.con cargas de 40,50 y 90 kg, respectivamente , se disponen a cruzar el rio. Se sabe que el bote solo puede tr

Veseljchak [2.6K]

10 y porque estas copiando

6 0

3 years ago

One student from the school will be selected at random. What is the probability the selected student chose the art elective and

Black_prince [1.1K]

Answer:

0

Step-by-step explanation:

The students are only allowed to take one slot for the elective. Therefore, there is a probability of zero that they would have chosen both art and music.

4 0

3 years ago

2. The Welcher Adult Intelligence Test Scale is composed of a number of subtests. On one subtest, the raw scores have a mean of

IgorC [24]

Answer:

a) 37.31 b) 42.70 c) 0.57 d) 0.09

Step-by-step explaanation:

We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., $\mu$ = 35 and $\sigma$ = 6. We know that the probability density function for a normal distribution with a mean of $\mu$ and a standard deviation of $\sigma$ is given by

$f(x) = \frac{1}{\sqrt{2\pi}\sigma}\exp[-\frac{(x-\mu)^{2}}{2\sigma^{2}}]$

in this case we have

$f(x) = \frac{1}{\sqrt{2\pi}6}\exp[-\frac{(x-35)^{2}}{2(6^{2})}]$

Let $X$ be the random variable that represents a row score, we find the values we are seeking in the following way

a) we are looking for a number $x_{0}$ such that

$P(X\leq x_{0})$ = $\int\limits^{x_{0}}_{-\infty} {f(x)} \, dx = 0.65$ , this number is $x_{0}$ =37.31

you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)

b) we are looking for a number $x_{1}$ such that

$P(X\leq x_{1})$ = $\int\limits^{x_{1}}_{-\infty} {f(x)} \, dx = 0.9$ , this number is $x_{1}$ =42.70

you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)

c) we find this probability as

$P(28\leq X\leq 38)$ = $\int\limits^{38}_{28} {f(x)} \, dx = 0.57$

you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)

d) we find this probability as

$P(41\leq X\leq 44)$ = $\int\limits^{44}_{41} {f(x)} \, dx = 0.09$

you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)

6 0

4 years ago

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