I think C Tell me if I’m wrong
<h3>
Answer:</h3>
25
<h3>
Step-by-step explanation:</h3>
Let w represent the weight of the animal in pounds, and d the age in days. The problem statement tells us ...
... w = 75 +2d
We want to find d when w > 125.
... 75 +2d > 125 . . . . . substitute the above expression for w
... 2d > 50 . . . . . . . . . subtract 75
... d > 25 . . . . . . . . . . . divide by 2
The animal will weigh more than 125 pounds when it is more than 25 days old.
Answer:
3/4
Step-by-step explanation:
You can do this two different ways. Both include picking two points where the line crosses a corner. I'm using (0,-1) and (4,2). Now here you can either use
Slope=
or
If you use the first one start at point (0,-1) and go to point (4,2) and count how many it goes up (rise) and then put that over how many it goes to the right (run).
If you use the second one then plug in the numbers.
y2=second y point
y1=first y point
x2=second x point
x1=first x point
Now just solve.

Given

We have to set the restraint

because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:

The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.
Similarly, we have

So, we have to impose

Squaring both sides, we have

The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.