The answer for the problem is A
The solution is not unique, but given that
, by the Pythagorean identity we have two solutions for
:
Then from this, we have two corresponding solutions for
. By definition,
and so we can have, in the case of
.
or
in the case that
.
Answer:
A quadratic equation ....[1] where, a, b and c are coefficient.
Then the solution is given by:
....[2]
As per the statement:
Given the equation:
⇒
On comparing with [1] we have;
a =1, b = 1 and c = -5
Then substitute these in [2] we have;
Therefore, the values of x are:
,
A; b; c; d = first; second; third; fourth shelfa + b + c + d = 250 cmb = 2a + 18c = a - 12d = a + 4in terms of a, plug all equations into originala + (2a + 18) + (a - 12) + (a +4) = 2505a + 10 = 2505a = 240a = 48b = 2(48) + 18b = 96 + 18b = 114 cm/1.14 m
Check the first picture. Our goal is to map <span>EFHG to E′F′H′G′.
</span>
All choices involve a rotation by 90° or 270°<span> counterclockwise about the origin.
consider a rotation </span>by 90° counterclockwise. Each point P(a, b) can be rotated 90° cwise about the origin to form P"(a",b") :
by drawing the right angle POP", such that |PO|=|OP"|.
or by plotting each P"(a",b") so that (a",b")=(-b, a)
for example if G(3, 1) is mapped to G(-1, 3) by either of the procedures described.
check picture 2.
EFHG is mapped to E′'F'′H'′G′'.
In order to map E′'F'′H'′G′' to E'F′H'G′, we need to translate the figure 1 unit right.
Answer:
"<span>A 90-degree counterclockwise rotation about the origin followed by a translation 1 unit to the right</span>"