1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sliva [168]
3 years ago
5

How do i write this in slope intercept form y=-3/4x+3​

Mathematics
1 answer:
zheka24 [161]3 years ago
3 0

Answer:

-3/4

Step-by-step explanation:

Slope: -3/4

hope this helps :)

You might be interested in
I'm have some issues with the problem shown in the screenshot and would love some help.
KiRa [710]

The dimensions and volume of the largest box formed by the 18 in. by 35 in. cardboard are;

  • Width ≈ 8.89 in., length ≈ 24.89 in., height ≈ 4.55 in.

  • Maximum volume of the box is approximately 1048.6 in.³

<h3>How can the dimensions and volume of the box be calculated?</h3>

The given dimensions of the cardboard are;

Width = 18 inches

Length = 35 inches

Let <em>x </em>represent the side lengths of the cut squares, we have;

Width of the box formed = 18 - 2•x

Length of the box = 35 - 2•x

Height of the box = x

Volume, <em>V</em>, of the box is therefore;

V = (18 - 2•x) × (35 - 2•x) × x = 4•x³ - 106•x² + 630•x

By differentiation, at the extreme locations, we have;

\frac{d V }{dx}  =  \frac{d( 4 \cdot \:  {x}^{3}  - 106 \cdot \:  {x}^{2}  + 630\cdot \:  {x} )  }{dx} = 0

Which gives;

\frac{d V }{dx}  =12\cdot \:  {x}^{2}  -  212\cdot \:  {x} + 630 = 0

6•x² - 106•x + 315 = 0

x  =  \frac{ - 6 \pm \sqrt{106 ^2 - 4 \times 6 \times 315} }{2 \times 6}

Therefore;

x ≈ 4.55, or x ≈ -5.55

When x ≈ 4.55, we have;

V = 4•x³ - 106•x² + 630•x

Which gives;

V ≈ 1048.6

When x ≈ -5.55, we have;

V ≈ -7450.8

The dimensions of the box that gives the maximum volume are therefore;

  • Width ≈ 18 - 2×4.55 in. = 8.89 in.

  • Length of the box ≈ 35 - 2×4.55 in. = 24.89 in.

  • Height = x ≈ 4.55 in.

  • The maximum volume of the box, <em>V </em><em> </em>≈ 1048.6 in.³

Learn more about differentiation and integration here:

brainly.com/question/13058734

#SPJ1

7 0
1 year ago
Help me please for brainlist
allochka39001 [22]

Answer:

b. 82m³

Step-by-step explanation:

V = \frac{1}{3}(\frac{1}{2} bh_1)h_2\\b = 8.2m\\h_1 =  4m\\h_2 = 15m\\\\V = \frac{1}{3}(\frac{1}{2}(8.2)(4))(15)\\V = 82m^{3}\\

3 0
3 years ago
Read 2 more answers
Help in this home work please
vlabodo [156]

Answer:

12.4 mg

3117.21 mg

1870.32 mg

Step-by-step explanation:

4 0
3 years ago
Last weekend, Charlie raked leaves in his front yard l. He noticed that 7/3 kilograms of leaves filled 4/9 of a bag. What is the
Archy [21]
7kg:4/9 bag
?kg:1 bag

7÷4/9 or 7×9/4=63/4 or 15.75. As a result, the unit rate is 15.75 kg of leaves per bag. Hope it help!
3 0
3 years ago
What is the cube root of 2197
kifflom [539]
13. I hope this helped. :) Brainliest answer please. :)
3 0
3 years ago
Read 2 more answers
Other questions:
  • The pie store is having a 55, percent off sale on all of its pies. If the pie you want regularly costs $7 how much would you sav
    8·1 answer
  • Which of the following expressions represents the sum of a number and three is divided by two? 2 ÷ x + 3 2 ÷ (x + 3) (x + 3) ÷ 2
    11·2 answers
  • Simplify 100<br> <br> A. 20<br> B. 10<br> C. -10<br> D. -25
    6·2 answers
  • Find the area of the shaded region. Round your answer to the nearest hundredth.
    12·1 answer
  • Mary picked 47 apples from the orchard, and gave 22 apples to Dan. How many apples does Mary have now
    10·2 answers
  • Need help with my geometry question please
    14·2 answers
  • Whats the answer lol
    10·2 answers
  • The lines 5x+2y=14 and y=-5x+9 are?<br> A: Parallel<br> B: Perpendicular <br> C: Neither
    14·1 answer
  • Find the equation of the circle whose diameter is the chord x + y = 3 of the circle x2 + y2 - 2x - 3 = 0​
    5·1 answer
  • Find the surface area of the composite figure.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!