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3 years ago

12

Pls help with logarithms I don’t get them

1 answer:

Anna [14]3 years ago

5 0

The answer for the problem is A

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There are 60 people in a class if 1/4 are absent how many peoples are presents<br><br>

igomit [66]

45 people are present

Explanation: 60x1/4=15
60-15=45

3 0

2 years ago

In a data distribution, the first quartile, the median and the means are 30.8, 48.5 and 42.0

kolbaska11 [484]

Answer:

$Q_3 = 56.45$ --- The third quartile

$Var = 370.18$ -- Variance

Step-by-step explanation:

Given

$Q_1 = 30.8$ -- First quartile

$Q_2 = 48.5$ --- Median

$\bar x = 42$ --- Mean

$Skp = -0.38$ --- Coefficient of skewness

Solving (9): The third quartile $Q_3$

This is calculated from

$Skp = \frac{Q_1 + Q_3 - 2Q_2}{Q_3 - Q_1}$

So, we have:

$-0.38 = \frac{30.8 + Q_3- 2*48.5}{Q_3 - 30.8}$

Cross Multiply

$-0.38 (Q_3 - 30.8)= 30.8 + Q_3- 2*48.5$

Open bracket

$-0.38Q_3 + 11.704= 30.8 + Q_3- 97.0$

Collect like terms

$-0.38Q_3 -Q_3= 30.8 - 97.0- 11.704$

$-1.38Q_3= -77.904$

Divide both sides -1.38

$Q_3 = \frac{-77.904}{-1.38}$

$Q_3 = 56.45$ --- approximated

Solving (b): The variance

First, calculate the standard deviation from:

$3IQR = 4SD$

$IQR= Q_3 - Q_1$

So:

$3IQR = 4SD$

$3(Q_3 - Q_1) = 4SD$

Make SD the subject

$SD = \frac{3}{4}(Q_3 - Q_1)$

$SD = \frac{3}{4}(56.45 - 30.8)$

$SD = \frac{3}{4}*25.65$

$SD = \frac{3*25.65}{4}$

$SD = \frac{76.95}{4}$

$SD = 19.24$

So, the variance is:

$Var = SD^2$

$Var = 19.24^2$

$Var = 370.18$

5 0

3 years ago

Katie wants to collect over 100100100 seashells. She already has 343434 seashells in her collection. Each day, she finds 121212

vekshin1

Answer:

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

Help I need help on all of them

Anettt [7]

I can't read the questions even after they are magnified. I have an idea, and I may be able to help you after, but you should do this:

Use the snipping tool to copy the answers down, then you should post.

I may be able to help you then if you share with the picture that way. Hope I was a little help!

3 0

4 years ago

Find the area of the region that is bounded by the given curve and lies in the specified sector. r = e−θ/6, π/2 ≤ θ ≤ π

anyanavicka [17]

I posted an image instead.

4 0

4 years ago