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vredina [299]
3 years ago
11

-1/-2*9*3/7what is -1 / -2 * 9 * 3/7

Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
7 0
27/14 or 1 13/14 or 1.928557143 either one is correct there just all simplified forms
KonstantinChe [14]3 years ago
4 0

-1/-2×9/1=9/2×3/7 9/2×3/7=27/14  I get 27/14

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Vince's birthday party is going to be at his favorite science museum next weekend. He has 8 friends who want to see the Dinosaur
Sunny_sXe [5.5K]

Answer:

See explanation

Step-by-step explanation:

Dinosaur Discovery show = 8 friends

Wild Weather show = 4 friends

Cost of Dinosaur Discovery show = $d

Cost of Wild Weather show = $w

At regular price:

Total cost of his friends' tickets = 8 * d + 4 * w

= 8d + 4w

At half price

Total cost of his friends' tickets =

8 * 1/2d + 4 * 1/2w

= 8/2d + 4/2w

= 4d + 2w

Total cost of his friends' tickets = 4d + 2w

6 0
3 years ago
A lines slope is 0, and it’s y intercept is 3. What is it’s equation in slope intercept form?
Zepler [3.9K]

Answer:

y=3

Step-by-step explanation:

y=mx+b where m = slope and b=y-intercept
slope: 0, y-intercept: 3

y=(0)x + 3

y=3

5 0
2 years ago
A local car dealer claims that 25% of all cars in San Francisco are blue. You take a random sample of 600 cars in San Francisco
sammy [17]

Answer:

No, we can't reject the dealer's claim with a significance level of 0.05.

Step-by-step explanation:

We are given that a local car dealer claims that 25% of all cars in San Francisco are blue.

You take a random sample of 600 cars in San Francisco and find that 141 are blue.

<u><em>Let p = proportion of all cars in San Francisco who are blue</em></u>

SO, Null Hypothesis, H_0 : p = 25%   {means that 25% of all cars in San Francisco are blue}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of all cars in San Francisco who are blue is different from 25%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 600 cars in San Francisco who are blue =   \frac{141}{600} = 0.235

            n = sample of cars = 600

So, <u><em>test statistics</em></u>  =  \frac{0.235-0.25}{{\sqrt{\frac{0.235(1-0.235)}{600} } } } }

                               =  -0.866

<em>Now at 0.05 significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that 25% of all cars in San Francisco are blue which means the dealer's claim was correct.

4 0
3 years ago
You draw one card from a? 52-card deck. then the card is replaced in the deck and the deck is? shuffled, and you draw again. fin
Solnce55 [7]

there are 4 tens in a deck so probability of picking a ten is 4/52 reduced to 1/13

 there are 13 clubs in a deck, probability for that is 13/52 reduced to 1/4

probability for both is 1/13 x 1/4 = 1/52

6 0
3 years ago
Point E is between points D and F. If DE = x − 2, EF = 6x + 4, and DF = 8x − 2, find x
Arlecino [84]
DE + EF = DF

x - 2 + 6x + 4 = 8x - 2
7x + 2 = 8x - 2
2 + 2 = 8x - 7x
4 = x <===
3 0
3 years ago
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