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melisa1 [442]
3 years ago
6

Three consecutive even integers whose sum is -48​

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
6 0
Three consecutive even integers whose sum is -48
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Martha is training for a duathlon, which includes biking and running. She knows that yesterday she covered a total distance of o
umka21 [38]

<u>Answer:</u>

<u>Distance:</u> 6x + 15.5y > 55.5

<u>Time:</u> x + y > 4.5

<u>Step-by-step explanation:</u>

We are given that Martha is training for a duathlon and she covered a total distance of over 55.5 miles in more than than 4.5 hours of training.

Also, she runs at a speed of 6 mph and bikes at a rate of 15.5 mph.

We are to write inequalities representing the distance she traveled and the total time she spent training.

<u>Distance:</u> 6x + 15.5y > 55.5

(formula for distance = speed x time so speeds for running and biking are multiplied by their number of hours)

<u>Time:</u> x + y > 4.5

(she trained for more than 4.5 hours, x hours for running and y hours for biking.

4 0
3 years ago
Solve for x: 6 + 3x = x - 8
djyliett [7]

Answer:

x = 1 + i √ 2 , 1 − i √ 2

Step-by-step explanation:

7 0
2 years ago
Choose the equation below that represents the line passing through the point (1, −4) with a slope of one half
murzikaleks [220]
Can I get a like plz
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2 years ago
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Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

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Local winds are created by _____.
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The correct answer is C.

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