Yes initial amount is 2044 (in millions)
Since the function is from 2000 then you can set it up as
B(t)=2044*a^t
To solve for "a" use the second number given, 3846, and since this value is 5 years after 2000 t=5
so we plug in these values
3846=2044*a^5
we now solve for a
first, divide by 2044
3846/2044=a^5
next, we take the 5th root
<span>5sqrt(3846/2044) = a
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Your answer will be negative because you're subtracting a greater value from a lesser value.
Yes 14% he got whatever the person on the top of me said
Answer:
the answer is below
Step-by-step explanation:
The z score is used to calculate by how many standard deviations the raw score is above or below the mean. The z score is given as:

1) For x = 3

For x = 6

P(3 ≤ x ≤ 6) = P(-0.5 ≤ z ≤ 1) = P(z < 1) - P(z < -0.5) = 0.8413 - 0.3085 = 0.5328
2) For x = 50

For x = 70

P(50 ≤ x ≤ 70) = P(0.67 ≤ z ≤ 2) = P(z < 2) - P(z < 0.67) = 0.9772 - 0.7486 = 0.2286
3) For x = 8

For x = 12

P(8 ≤ x ≤ 12) = P(-2.19 ≤ z ≤ -0.94) = P(z < -0.94) - P(z < -2.19) = 0.1736 - 0.0143 = 0.1593
4) For x = 30

P(x ≥ 30) = P(z ≥ 2.94) = 1 - P(z < 2.94) = 1 - 0.9984 = 0.0016
5) x = 90

P(x ≥ 90) = P(z ≥ -0.67) = 1 - P(z < -0.67) = 1 - 0.2514 = 0.7486
6) For x = 10

For x = 20

P(10 ≤ x ≤ 20) = P(-1.25 ≤ z ≤ 1.25) = P(z < 1.25) - P(z < -1.25) = 0.8944 - 0.1056 = 0.7888
7) For x = 7

For x = 9

P(7 ≤ x ≤ 9) = P(1.67 ≤ z ≤ 3.33) = P(z < 3.33) - P(z < 1.67) = 0.9996 - 0.9525 = 0.0471
8) For x = 40

For x = 47

P(40 ≤ x ≤ 47) = P(-0.67 ≤ z ≤ -0.2) = P(z < -0.2) - P(z < -0.67) = 0.4207 - 0.2514 = 0.1693
9) x = 120

P(x ≥ 120) = P(z ≥ 7.33) = 1 - P(z < 7.33) = 1 - 0.9999 = 0.001
10) x = 2

P(x ≥ 2) = P(z ≥ -4) = 1 - P(z < -4) = 1 - 0.0001 = 0.999