What are the center and the radius of the circle whose equation is (x-5)^2+(y+3)^2=16

Mathematics

2 answers:

Sindrei [870]3 years ago

5 0

CENTER : ( 5, -3)

RADIUS : 4

Setler [38]3 years ago

4 0

Answer:

Center (5,-3)

radius : 4

Step-by-step explanation:

Radius: is the square root of 16. The square root of 16 = +/- 4. Minus 4 has absolutely no meaning for a question like this so the radius is 4. Rule take the square root of the counting number on the right.

The center is the value when x - 5 =0 and y + 3 = 0

x - 5 = 0

x = 5

y + 3 = 0

y = -3

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