PLZ NEED HELP ASAP !!!!

Biology

1 answer:

-BARSIC- [3]3 years ago

7 0

Answer:

(I will number the boxes from top to bottom)

1. DNA Polymerase

2. Topoisomerase

3. Okazaki Fragment

4. DNA Helicase

5. RNA Primase

I hope this helps! Let me know if you need further guidance.

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Shalnov [3]

Answer:

its a

Explanation:

eukarya and eukaryotic see the similarities?

6 0

3 years ago

Read 2 more answers

Which of the following results from a mark-recapture study done on mice would reflect a larger population size? When taking the

Lubov Fominskaja [6]

Answer:

Option (3).

Explanation:

Mark recapture method is used for the estimation of population size of an area. The individuals are identified by some mark on them. The formula of mark recapture method is

N = M * C/ R

Here, N is the number of the individuals, M is the individuals are marked and captured, C is the individual captured again with mark or non mark and R is recaptured marked individual.

The individual with 200 population, 20 are marked for the first time represent the large population size.

Thus, the correct answer is option (3).

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3 years ago

of the two cells represented in the figure, which would likely be more efficient at exchanging substances with the surrounding e

tia_tia [17]

Cell A is more efficient at exchanging substances due to larger surface area to volume ratio.

Cell A is more efficient at exchanging substances with the surrounding environment than cell B because it has the larger surface-area-to-volume ratio. Larger surface area of the cell exchanges more substances with the surrounding environment while on the other hand, lower surface area of the cell exchanges less materials with the environment so we can conclude that cell A is more efficient at exchanging substances due to larger surface area to volume ratio.