Answer:
this is the answer
Step-by-step explanation:
hope it helped!!!
25points for this question Given: AB ≅ BC and AO ≅ OC OK − angle bisector of ∠BOC Find: m∠AOK
1 answer:
- AB and BC are congruent (given)
- AO and OC are congruent (given)
- BO is congruent with itself (reflexivity)
Taken together, these three facts imply that triangles AOB and COB are congruent (side-side-side congruence postulate).
Now, it's not exactly clear whether A and C lie on the same line (it's possible that the figure is not drawn to scale). If they do, then both angles AOB and COB are right angles, so angle BOK has measure 45º, and so .
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Answer:
B. It will be the tens place because 6 is greater than 3.
Step-by-step explanation:
Since the question said "quotient," then I believe we have 362 ÷ 6 and not "362 + 6."
If we work on the quotient we have
Obviously, the first digit in the quotient is 6 and it takes the place of tens.
Looking at the options, option B fits the most because 6 is actually greater than 3.
Therefore, the answer is option B, It will be the tens place because 6 is greater than 3.