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2 years ago

Answer the questions and answer the questions please please please please please

Mathematics

1 answer:

dolphi86 [110]2 years ago

4 0

42% of 50 => 42.50/100 = 21
110% of 80 => 110.80/100=88
50% of 56 => 50.56/100=28

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10 + 6x + 2x - 7 = 35<br> Help me pls and ty

lutik1710 [3]

Answer:

Explanation:

10 + 6x + 2x - 7 = 35

Add Similar Elements: 6x + 2x = 8x

10 + 8x - 7 = 35

Group Like Terms

8x + 10 - 7 = 35

Subtract: 10 - 7 = 3

8x + 3 = 35

Subtract 3 From Both Sides

8x + 3 - 3 = 35 - 3

Simplify

8x = 32

Divide Both Sides By 8

8x / 8 = 32 / 8

6 0

3 years ago

Read 2 more answers

Calculate the volume and area of a rectangular prism that measures 5cm x 9cm and 11cm high at the base

gogolik [260]

Answer:

495 cm3

Step-by-step explanation:

5x9x11

3 0

3 years ago

For a field trip, the school bought 23 sandwiches for $4.60 each and 5 bags of chips for $1.25 each. How much did the school spe

Verizon [17]

Answer:

112.05

Step-by-step explanation:

i did 23 times 4.60 then 5 times 1.25 then add the answers

hope this helps

-mercury

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2

Nimfa-mama [501]

First of all, we can observe that

$x^2-6x+9 = (x-3)^2$

So the expression becomes

$\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}$

This means that the expression is defined for every $x\neq 3$

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

$x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2$

Since we can't accept 3 as an answer, the actual solution set is

$(-\infty,-2] \cup [2,3) \cup (3,\infty)$

7 0

2 years ago

How do you find the slope of the line that goes<br> through the points (-5, 6) and (7,-6)?

strojnjashka [21]

Answer:

Step-by-step explanation:

$slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{-6-6}{7-[-5]}\\\\=\frac{-12}{7+5}\\\\=\frac{-12}{12}\\\\=-1$

5 0

3 years ago

Answer the questions and answer the questions please please please please please ​

Answer the questions and answer the questions please please please please please