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Alborosie
3 years ago
7

Calculate: 0.3 of 14

Mathematics
2 answers:
jasenka [17]3 years ago
8 0

100% --> 14

30% --> x

100x = 420

x= 420/100

x=4.2


Ber [7]3 years ago
7 0

Answer:

The answer is 4.2

Step-by-step explanation:

Always remember that when they use the word of, it means you have to multiply. So 14 times 0.3 is 4.2

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Write the equation in slope-intercept form in each line based on the information give
olchik [2.2K]

Answer:

y= 6x -8

Step-by-step explanation:

<u>Slope-intercept form: </u>

y= mx +c, where m is the gradient and c is the y-intercept.

\boxed{gradient =  \frac{y1 - y2}{x1- x2} }

Gradient

=  \frac{4 - ( - 2)}{2 - 1}

= 6

y= 6x +c

To find the value of c, substitute the equation with a pair of coordinates.

When x= 1, y= -2,

-2= 6(1) +c

c= -2 -6 <em>(</em><em>-6</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

c= -8

Thus, the equation of the line is y= 6x -8.

8 0
3 years ago
An experiment repeated 5 times is more reliable than an experimment repeated 20 times
shutvik [7]

Answer:

The given statement is false

Step-by-step explanation:

Given that an experiment repeated 5 times is more reliable than an experiment repeated 20 times.

The statement is false.

Any result found by way of experiment will be more reliable if more number of trials are done.  

For example, consider toss of a coin.  If we try for 2 times, we may get prob for head as 0 sometimes 1/2 or sometimes 1. This is because 2 is very short number of trials to decide.  But when you increase to 10, you may get more reliable.  SO if number of repititions increase, the more reliable the results would be.

8 0
3 years ago
Select all the statements that are true for the following systems of equations
Aleks [24]

Answer:

A. System C simplifies to 2x - 3y = 4 and 4x - y = 54 by dividing the second equation by three (3).

B. Systems A and C have the same solutions.

C. Systems A and B have different solutions.

Step-by-step explanation:

Given the following system of equations;

<em><u>System A</u></em>

2x - 3y = 4  .....equation 1

4x - y = 18  .......equation 2

We would solve the above equations using the elimination method;

Multiplying eqn 1 by 2;

2*(2x) - 2*(3y) = 4*2

4x - 6y = 8  ...... equation 3

Subtracting eqn 2 from eqn 3;

(4x - 4x) + (-6y - (-y)) = 8 - 18

0 + (-6y + y) = -10

-5y = -10

5y = 10

y = \frac {10}{5}

y = 2

To find the value of x;

2x - 3y = 4

2x - 3(2) = 4

2x - 6 = 4

2x = 4 + 6

2x = 10

x = \frac {10}{2}

x = 5

<em><u>Solutions (x, y) = (5, 2)</u></em>

<u><em>System B</em></u>

3x - 4y = 5  ..... equation 1

y = 5x + 3  ..... equation 2

We would solve the equations using substitution method;

Substituting eqn 2 into eqn 1, we have;

3x - 4(5x + 3) = 5

3x - 20x - 12 = 5

-17x - 12 = 5

-17x = 12 + 5

-17x = 17

x = \frac {-17}{17}

x = -1

To find the value of y;

y = 5x + 3

y = 5(-1) + 3

y = -5 + 3

y = -2

<u><em>Solutions (x, y) = (-1, -2)</em></u>

<u><em>System C</em></u>

2x - 3y = 4  ..... equation 1

12x - 3y = 54  ...... equation 2

We would solve the above equations using the elimination method;

Subtracting eqn 2 from eqn 1;

(2x - 12x) + (-3y -(-3y)) = 4 - 54

-10x + (-3y + 3y) = -50

-10x + 0 = -50

-10x = -50

10x = 50

x = \frac {50}{10}

x = 5

To find the value of y;

2x - 3y = 4

2(5) - 3y = 4

10 - 3y = 4

3y = 10 - 4

3y = 6

y = \frac {6}{3}

y = 2

<u><em>Solutions (x, y) = (5, 2)</em></u>

5 0
2 years ago
What is the solution of the equation when solved over the complex numbers?
marishachu [46]

Try this option:

x²+27=0;

(x+\sqrt{-27})(x- \sqrt{-27})=0; \ => \ \left[\begin{array}{ccc}x=3 \sqrt{3}i\\x=-3 \sqrt{3}i \end{array}\right

3 0
2 years ago
Read 2 more answers
X plus 1/3 equals nine enter your answer in the box in simplest form
LekaFEV [45]


= > x + \frac{1}{3} = 9



\text{Add} \: - \frac{1}{3} \: \text{ on both sides ,}



= > x + \frac{1}{3} - \frac{1}{3} = 9 - \frac{1}{3} \\ \\ \\ \\ = > x = \frac{(9 \times 3) - 1}{3} \\ \\ \\ \\ = > x = \frac{27 - 1}{3} \\ \\ \\ \boxed{ \bold{= > x = \frac{26}{3} }} \\ \\ \\ or , \boxed{ \bold{ \: x = 8. \bar{6}}}




Hence,


Value \: \: \: of \: \: x \: \: is \:  \frac{26}{3} \: \: \: or \: \: \: 8. \bar{6}
5 0
3 years ago
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