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3 years ago

What is 375 as the product of prime factors

1 answer:

6 0

Answer: 375 is a composite number. Prime factorization: 375 = 3 x 5 x 5 x 5, which can be written 375 = 3 x (5^3) The exponents in the prime factorization is 1

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Find the Area. Simplify your answer.

Vaselesa [24]

Answer:

Area = $9x^2$ square units

Step-by-step explanation:

Key skills needed: Area of a parallelogram

1) This shape is a parallelogram, and the way to find the area of a parallelogram is:

$A = bh$

A = area

b = base (the side at the bottom

h = the height ( the length that runs from one side to another and makes a right angle)

2) The base (b) would be 3x. The height (h) would also be 3x

3) This means A = $3x(3x)$

3 times 3 is 9 --> and x times x is $x^2$

Therefore the area is --> $9x^2$

Hope you understood and have a nice day!! :D

5 0

3 years ago

State the y-coordinate of the y-intercept for the function below.

marta [7]

Answer:

Step-by-step explanation:

y-intercept is defined as the point where the graph crosses the y-axis. The value of x coordinate at this point is zero, as along entire y-axis, the value of x coordinate is always zero. So substituting x = 0 in the function will give us the y-coordinate of the y-intercept of the given function.

$f(x)=x^{3}-x^{2} -x+1$

Substituting x = 0 in this function, we get:

$f(0)=0^{3}-0^{2}-0+1=1$

Thus, the y-coordinate of the y-intercept is 1. Therefore the y-intercept of the function in ordered pair will be: (0, 1)

3 0

3 years ago

What is: -24 - (-64)

Triss [41]

Answer:

Step-by-step explanation:

Calculator.

6 0

2 years ago

Read 2 more answers

Please need some help on this

vredina [299]

11111111111111117373646328299292922

8 0

3 years ago

Find the derivative of f(x) = 2x^2 - 4x +3

ivolga24 [154]

Explanation

$2x^2-4x+3$

When taking derivatives of polynomials, we primarily make use of the power rule.

Power rule.

$\begin{gathered} f(x)=x^n \\ \text{then} \\ f^{\prime}(x)=nx^{n-1} \end{gathered}$

also, the derivate of a sum is the sum of the derivates

hence

$\begin{gathered} g(x)=f(x)+h(x)+\ldots z(x) \\ g^{\prime}(x)=f^{\prime}(x)+h^{\prime}(x)+\ldots.z^{\prime}(x) \end{gathered}$

Step 1

apply:

$\begin{gathered} f(x)=2x^2-4x+3 \\ f^{\prime}(x)=2\cdot2x^{2-1}-4(1)x^{1-1}+ \\ f^{\prime}(x)=4x^{}-4(1)x^0+3^0 \\ f^{\prime}(x)=4x^{}-4(1)(1) \\ f^{\prime}(x)=4z-4 \end{gathered}$

therefore, the answer is

8 0

1 year ago