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Snowcat [4.5K]
3 years ago
5

What is 375 as the product of prime factors

Mathematics
1 answer:
crimeas [40]3 years ago
6 0

Answer: 375 is a composite number. Prime factorization: 375 = 3 x 5 x 5 x 5, which can be written 375 = 3 x (5^3) The exponents in the prime factorization is 1

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dusya [7]
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0.12 =3/25

The work is included if needed
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3y''-6y'+6y=e*x sexcx
Simora [160]
From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

3r^2-6r+6=0\iff r^2-2r+2=0

which has roots at r=1\pm i. This admits the two fundamental solutions

y_1=e^x\cos x
y_2=e^x\sin x

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

y_p=u_1y_1+u_2y_2

where

u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx
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and W(y_1,y_2) is the Wronskian of the fundamental solutions. We have

W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}

and so

u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx
u_1=\dfrac13\ln|\cos x|

u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx
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Therefore the particular solution is

y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x

so that the general solution to the ODE is

y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x
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3 years ago
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Answer:

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Step-by-step explanation:

explanation attached. brainliest would be nice.

6 0
2 years ago
Zohar is using scissors to cut a rectangle with a length of 5x – 2 and a width of 3x + 1 out of a larger piece of paper. Which e
sweet-ann [11.9K]

Answer with Step-by-step explanation:

Zohar cut a rectangle with a length of 5x – 2

and a width of 3x + 1

We know that:

Perimeter of rectangle is:

Perimeter=2(length+width)

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Can anyone explain this question to me? My teacher solved it but I didn’t understand how she did it
Amiraneli [1.4K]

Step-by-step explanation:

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So, the volume of the first block is 54 cm³.

To this, we will add the volume of the blue block. We can find its dimensions with some simple deduction.

The picture shows that the height of the figure is 4cm less than the height of the green one, 6cm.

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The height, then, is 2cm.

The width can be found by subtracting the width of the green block from the total width of both figures, 5cm.

5 - 3 = 2

So, the width is also 2cm.

We can see that the length of the blue block is equal to that of the green one, so we know that the length is 3cm.

Now, multiply all the dimensions we have found together.

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We have found the volumes of both figures, so now we can add them both together to find the total.

54 + 12 = 66

So, the total volume is 66cm³.

I hope this was a satisfactory explanation ^^ Good luck, mate

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2 years ago
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