All categories

2 years ago

Need help with this i don't understand

Mathematics

1 answer:

Oksana_A [137]2 years ago

5 0

Answer:

7
see below
5
the rule is not one-to-one

Step-by-step explanation:

Applying the squaring rule to each of the elements of the domain, we get ...

$\begin{array}{cc}\text{Domain}&\text{Range}\\1&1\\-3&9\\-\frac{1}{2}&\frac{1}{4}\\3&9\\2&4\\\frac{1}{4}&\frac{1}{16}\\0.5&\frac{1}{4}\end{array}$

1. There are 7 different numbers in the Domain list.

2. See above

3. There are 5 different numbers in the Range list.

4. The rule "square me" is not "one-to-one" Two different values in the domain can result in the same value in the range. -3 and 3 both result in 9. -1/2 and 0.5 both result in 1/4.

You might be interested in

For f(x)-4x+1 and g(x)-x^2-5, find (g/f) (x)

antoniya [11.8K]

Answer:

Step-by-step explanation:

let me know if you want an explanation :))

8 0

2 years ago

Read 2 more answers

The length of time a person takes to decide which shoes to purchase is normally distributed with a mean of 8.21 minutes and a st

madam [21]

Answer:

4.55% probability that a randomly selected individual will take less than 5 minutes to select a shoe purchase.

Since Z > -2 and Z < 2, this outcome is not considered unusual.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If $Z \leq 2$ or $Z \geq 2$ , the outcome X is considered to be unusual.

In this question:

$\mu = 8.21, \sigma = 1.9$

Find the probability that a randomly selected individual will take less than 5 minutes to select a shoe purchase.

This is the pvalue of Z when X = 5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5 - 8.21}{1.9}$

$Z = -1.69$

$Z = -1.69$ has a pvalue of 0.0455.

4.55% probability that a randomly selected individual will take less than 5 minutes to select a shoe purchase.

Since Z > -2 and Z < 2, this outcome is not considered unusual.

8 0

3 years ago

The graph below is the solution for which sets of inequalities?

Reil [10]

Answer:

the first one

Step-by-step explanation:

i did the test and got it right

8 0

3 years ago

A water container has 19.5 litres of water in it. A cup holds 210 ml of water. At most 92 cups can be filled completely from the

coldgirl [10]

Step-by-step explanation:

Given

A container has 19.5 liters of water

A cup can hold 210 ml of water

1 L is equivalent to 1000 ml

So, 19.5 L is equivalent to $19.5\times 1000=19,500\ ml$

So, the number of requires to hold this much water

$\Rightarrow n=\dfrac{19,500}{210}\\\\\Rightarrow n=92.85\ \text{cups}$

92.85 implies 92 full cups and 1 cup which is partially filled. Hence, almost 92 cups can be filled completely.

5 0

2 years ago

A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) A

julsineya [31]

Answer:

a) -13.9 ft/s

b) 13.9 ft/s

Step-by-step explanation:

a) The rate of his distance from the second base when he is halfway to first base can be found by differentiating the following Pythagorean theorem equation respect t:

$D^{2} = (90 - x)^{2} + 90^{2}$ (1)

$\frac{d(D^{2})}{dt} = \frac{d(90 - x)^{2} + 90^{2})}{dt}$

$2D\frac{d(D)}{dt} = \frac{d((90 - x)^{2})}{dt}$

$D\frac{d(D)}{dt} = -(90 - x) \frac{dx}{dt}$ (2)

Since:

$D = \sqrt{(90 -x)^{2} + 90^{2}}$

When x = 45 (the batter is halfway to first base), D is:

$D = \sqrt{(90 - 45)^{2} + 90^{2}} = 100. 62$

Now, by introducing D = 100.62, x = 45 and dx/dt = 31 into equation (2) we have:

$100.62 \frac{d(D)}{dt} = -(90 - 45)*31$

$\frac{d(D)}{dt} = -\frac{(90 - 45)*31}{100.62} = -13.9 ft/s$

Hence, the rate of his distance from second base decreasing when he is halfway to first base is -13.9 ft/s.

b) The rate of his distance from third base increasing at the same moment is given by differentiating the folowing Pythagorean theorem equation respect t:

$D^{2} = 90^{2} + x^{2}$