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3 years ago

3m-2x For m=5 and x= 4

2 answers:

6 0

Hi there! The answer is 7.

To find our answer we need to plug in m = 5 and x = 4 into the expression.

We find the following
$3m - 2x = 3 \times 5 - 2 \times 4$

Multiply first.
$3 \times 5 - 2 \times 4 = 15 - 8$

Now subtract.
$15 - 8 = 7$

The answer is 7.
~ Hope this helps you!

Kipish [7]3 years ago

6 0

Hi there!

3m - 2x

• x = 4
• m = 5

Substitute th' value of " x " and " m " in the following expression.

=> 3 × 5 - 2 × 4

=> 15 - 8

=> 7

Hence,
The required answer is $7$

~ Hope it helps!

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4 years ago

Which set of numbers does not contain the value below?

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Answer:

b. Pure Imaginary Numbers.

Step-by-step explanation:

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-3 is an integer, a complex number, and a rational number.

Answer: b. Pure Imaginary Numbers.

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3 years ago

Simplify mentally 4867.293 ÷ 1000

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3 years ago

Help with this question(Will give brianlist and thanks)(Determine the area)

lana [24]

Answer:

The area of trapezium is (x+11) cm².

Step-by-step explanation:

Given that the formula of area of trapezium is :

$area = \frac{1}{2} \times (a + b) \times h$

In the formula, a and b represents the length of trapezium and h is the height. So you have to substitute the following expressions into the formula :

$let \: a = 5 \\ let \: b = x + 6 \\ let \: h = 2$

$area = \frac{1}{2} \times (5 + x + 6) \times 2$

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3 0

4 years ago

Read 2 more answers

You have $6000 with which to build a rectangular enclosure with fencing. The fencing material costs $30 per meter. You also want

Roman55 [17]

Refer to the figure shown below.
x = the width of the rectangle (meters)
y = the height of the rectangle (meters(

The fencing for the perimeter of the rectangle costs $30 per meter.
The two inner partitions cost $25 per meter.

The total cost of the fencing is
C = 2(x+y)*$30 + 2y*$25
= 60(x+y) + 50y
= 60x + 110y

Because the amount available to spend is $600, therefore
60x + 110y = 6000
or
6x + 11y = 600
That is,
y = (600 - 6x)/11 (1)

The area is
A = x*y (2)

Substitute (1) into (2).
A = (x/11)*(600 - 6x) = (1/11)*(600x - 6x²)

To maximize A, the derivative of A with respect to x is zero.
That is,
600 - 12x = 0
x = 600/12 = 50
From (1), obtain
y = (1/11)*(600 - 6*50) = 300/11 = 27.273

Because the second derivative of A with respect to x is negative, x=50, y = 27.273 will yield the maximum area.

The maximum area is
50*27.273 = 1363.64 m² = 1364 m² (nearest integer)

Answer: 1364 m² (nearest integer)

5 0

3 years ago